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KengaRu [80]
2 years ago
6

Write the expression in exponential form.

Mathematics
1 answer:
omeli [17]2 years ago
3 0
(3 root a)^2 hope this helps
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I need the answer for 21
levacccp [35]

Answer:

h>13

Step-by-step explanation:

3 0
3 years ago
Having trouble w graphing :(
NISA [10]

6x/6=x>/= (=) 11/6

x=11/6 or about 1.8

the first important notation to remember when graphing inequalities is that the graph is going to face the way the inequality sign is pointing.

in this case, the sign is pointing right. now the second thing to remember is that an inequality sign with a line underneath it means that it is greater/equal to so the graph in which we fill will have be a closed circle

1) start the ray at ~1.8 and fill in the circle at the end of the ray then extend to its endpoint

that's all. you're graph now reads  x is greater or equal to 11/6

3 0
3 years ago
What is 40%x2/3 x 24 divided by 0.8?
tino4ka555 [31]
8

Reduce the expression, if possibel, by cancelling the common factors
7 0
3 years ago
Read 2 more answers
A line has x-intercept of 6 and y-intercept of -4.Find the slope of the line.
Zigmanuir [339]

x-intercept is 6, coordinates (6,0)

y-intercept -4, coordinates (0,-4)

gradient= y1-y2/x1-x2= 0-(-4)/6-0= 4/6= 2/3 or 0.667 (3.s.f.)

3 0
3 years ago
Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

8 0
3 years ago
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