What are the coordinates of the circumcenter of a triangle with vertices A(−3, 3) , B(−1, 3) , and C(−1, −1) ?

2 answers:

8 0

Hello Missjay12,

Step 1 :
From the coordinates we have to find the slopes and midpoints of the lines.

Step 2 :
Find the slope of the bisectors and now find the equations of two lines by using slope and one mid points.

Step 3 :
Solve any two pair of equations and find the intersection point.

Step 4 :
The point thus found is the circumcenter of the given triangle.

so<span> the coordinates of the circumcenter of a triangle with vertices A(−3, 3) , B(−1, 3) , and C(−1, −1)</span> is, -4, 0.

Elenna [48]3 years ago

6 0

Answer:

I just took the quiz its -2, -1

Step-by-step explanation:

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I need help with this please

AnnZ [28]

Hi there! The answer is C.

The area of the square in the middle is the following:
$length \: \times \: width \: = 5 \times 5 = 25$
Hence, the area of the square is 25 cm^2.

The area of one triangle is the following:
$0.5 \times base \: \times \: height \: = 0.5 \times 5 \times 8 = 20$
Hence, the total area of the four triangles is 4 × 20 = 80 cm^2.

Therefore, the total area of the pyramid is 80 + 25 = 105 cm^2. The answer is C.

6 0

3 years ago

Read 2 more answers

8 + 4f = 3f solve for f

navik [9.2K]

Answer:

$f=-8$

Step-by-step explanation:

$8+4f=3f$

$8+4f-4f=3f-4f$ (Subtract $4f$ from both sides of the equation to isolate $f$ )

$8=-f$ (Simplify)

$-f=8$ (Symmetric Property of Equality)

$\frac{-f}{-1} =\frac{8}{-1}$ (Divide both sides of the equation by $-1$ to get rid of $f$ 's coefficient; remember that $-f=-1*f$ , so $-f$ has a coefficient of $-1$ )