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LiRa [457]
2 years ago
12

For each equation, decide if it is always true or never true. x − 13 = x + 1 x + 1 2 = x − 1 2 2 ( x + 3 ) = 5 x + 6 − 3 x x − 3

= 2 x − 3 − x
Mathematics
1 answer:
mrs_skeptik [129]2 years ago
6 0

"x" (and any subsequent words) was ignored because we limit queries to 32 words.

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the cylinder has radius 4√3 and hight h. the total surface area of the cylinder is 56π√6. find the exact value of h giving the a
Arte-miy333 [17]

The area of the cylinder is a function of its height (h) and radius, (\mathbf{4\sqrt 3})

The exact value of h is: \mathbf{7\sqrt 2- 4\sqrt 3}

The given parameters are:

\mathbf{Area =56\pi\sqrt 6}

\mathbf{r=4\sqrt 3}

The surface area of a cylinder is calculated as:

\mathbf{Area = 2\pi rh + 2\pi r^2}

Substitute values for Area

\mathbf{56\pi\sqrt 6= 2\pi rh + 2\pi r^2}

Divide through by pi

\mathbf{56\sqrt 6= 2 rh + 2r^2}

Substitute value for r

\mathbf{56\sqrt 6= 2 (4\sqrt 3)h + 2(4\sqrt 3)^2}

\mathbf{56\sqrt 6= 8h\sqrt 3 + 2\times 48}

\mathbf{56\sqrt 6= 8h\sqrt 3 + 96}

Collect like terms

\mathbf{8h\sqrt 3 = 56\sqrt 6- 96}

Make h the subject

\mathbf{h = \frac{56\sqrt 6}{8\sqrt 3}- \frac{96}{8\sqrt 3}}

\mathbf{h = 7\sqrt 2- \frac{12}{\sqrt 3}}

Rationalize

\mathbf{h = 7\sqrt 2- \frac{12\sqrt 3}{3}}

\mathbf{h = 7\sqrt 2- 4\sqrt 3}

Hence, the exact value of h is: \mathbf{7\sqrt 2- 4\sqrt 3}

Read more about surface areas t:

brainly.com/question/25131428

5 0
2 years ago
What is the length of the base of a right triangle with an area of 15 square meters and a height of 3 meters? A. 5 m B. 10 m C.
Rzqust [24]

Answer:

B.10

Step-by-step explanation:

15=1/2b(3)

30=3b

10= base

4 0
2 years ago
PLEASE HELP!
Kitty [74]
You can reword the two equations as:

-5x-y=15 (Divide original value by 3)
-2x+6y=6

Then use elimination to find x:

-30x-6y=90 (Multiply by 6 to get y values to be same to cancel out)
-2x+6y=6

You're left with:

-32x=96. Which can then be solved to find x which is -3.

Then plug back in 

-2x+6y=6

Now to: -2(-3)+6y=6.

Which reduces to 6+6y=6. So y=0.



To graph them, just reword the equations (yes once again) so that y is in front.

y=-5x-15 and y=(1/3)x+1






8 0
3 years ago
These two polygons are similar. ​
Nady [450]

9

yea........ hi how you doinn

4 0
2 years ago
What is the value of this expression when x=-1 and Y = 2?<br> 4x3y2
3241004551 [841]
-48 plugging in everything and using PEMDAS it should be -48
8 0
2 years ago
Read 2 more answers
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