Question

A normal distribution has a mean of 10 and a standard deviation of 1. What is the probability of selecting a number that is at most 10? Leave the answer in decimal form to 3 decimal places.​

Answer 1

Answer: 0.500

Step-by-step explanation:

Given : A normal distribution has a mean$(\mu)$ of 10 and a standard deviation$(\sigma)$ of 1.

Let x be a random variable that represents numbers .

The probability of selecting a number that is at most 10 will be

$P(x\leq10)=P(\dfrac{x-\mu}{\sigma}\leq\dfrac{10-10}{1})\\\\=P(z\leq0)=0.500$

As the area occupied by standard normal curve less than equal to 0 = 0.500

So, required probability = 0.500