Evaluate 7-5{p}+3q7−5p+3q7, minus, 5, p, plus, 3, q when p=1p=1p, equals, 1 and q=7q=7q, equals, 7.
Inessa05 [86]
Answer:
Its 23
Step-by-step explanation:
7 – 5p + 3q
= 7 – 5(1) + 3(7)
= 7 – 5 + 21
= 28 – 5
= 23
Answer:
∠1=66⁰
∠2=24⁰
∠3=24⁰
∠4=90⁰
Step-by-step explanation:
∠2=∠ADB=24 (ΔADB is isosceles, so ∠ADB=∠ABD)
∠4 =90 (right angle)
∠3=24 (BD bisects ∠ABC, so ∠2=∠3)
∠1+∠2+90=180 (angles in triangle add to 180)
∠1=66
Is there any more to the problem?
Answer:
48
Step-by-step explanation:
We are asked that the value of (4n + 7) will be an integer > 1 and < 200, for how many integer values of n.
So, equating (4n + 7) with 200 we can get the value.
4n + 7 = 200
⇒ 4n = 193
⇒ n = 48.25
Hence, the value of n will be the largest integer less than 48.25.
Therefore, the number of integer values of n will be 48. (Answer)
Answer:
x =
Step-by-step explanation:
a is the hypotenuse of the right angled triangle ehereas the other two sides are legs of a right angle triangle .
since the other two sides are equal both should be denoted as x.
now the value of a is given i.e 14 m
using pythagoras theorem,
pythagoras theorem states that sum of square of two smaller sides of a right triangle is equal to the sum of square of hypotenuse. so,
a^2 + b^2 = c^2
x^2 + x^2 = 14^2
2x^2 = 196
x^2 = 196/2
x^2 = 98
x =
x =