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Ksenya-84 [330]
3 years ago
14

Collins Middle School has 192 sixth grade students. If the sixth grade is 30% of the total school, how many students are in the

middle school?
Mathematics
2 answers:
Sophie [7]3 years ago
4 0
The answer is 640 because if you multiply the total student of 6h grade by 100 and divide by 30. You will get the total of student in the school
Serjik [45]3 years ago
3 0
I believe the answer is 640 students. To get this answer you need to divide 192 by 30% in decimal form so it would look like 192/0.30 and that should get you 640 students!!!

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julie goes to the park across the street from her house several times a day and jogs a total of six miles every day. she jogs th
Semmy [17]
Julie jogs 0.75miles each time. set 'x' to represent the unknown number of times. Total distance for the day is 6 miles. So, you multiply the distance of each run 0.75 times 'x' (unknown number of runs) and set this equal to 6 miles.
0.75x = 6   (divide each side by 0.75)
8 = x 

She ran 8 times each day.
4 0
3 years ago
If the radius of a circle with an area of 11.5 inches squared is multiplied by 6, what is the area of the new circle?
Zanzabum

Answer:

<u>The correct answer is D. 414 in squared.</u>

Step-by-step explanation:

1. Let's review the information given to us for solving the question:

Area of the first circle = 11.5 inches ²

2. Let's calculate the area of the new circle, given that the radius of the first circle is multiplied by 6.

Area of the first circle = 11.5 inches ²

Let's find the radius:

π * r² = 11.5

r² = 11.5 / 3.1416

r² = 3.66055513

r = 1.91 inches

The first circle has a radius of 1.91 inches

So, the radius of the second circle is 1.91 * 6 = 11.48 inches

Area of the second circle = π * r²

Area of the second circle = 3.1416 * 11.48²

Area of the second circle = 3.1416 * 131.79

Area of the second circle = 414.03 inches ²

<u>Area of the second circle = 414 inches ² (Rounded to the nearest whole number)</u>

<u>The correct answer is D. 414 in squared.</u>

8 0
3 years ago
Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartF
Firdavs [7]

The length 2.3 and 7.8 units

We have given that ΔABC, c = 5. 4, a = 3. 3, and measure of angle A = 20 degrees.

<h3>What is the formula for low of cosine?</h3>

The Law of Cosines, which tells us

a^{2}=b^{2} +c^{2} -2bccosA

giving us a quadratic equation for b we can solve.  But let's do it with the Law of Sines as asked.

\frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c}

We have c,a,A so the Law of Sines gives us sin C

sinC=\frac{csina}{a} =\frac{5.4sin20}{3.3} =0.5597

There are two possible triangle angles with this sine, supplementary angles, one acute, one obtuse

C_{a}=arcsin(0.5597)=34.033^{0}

C_{0}=180-C_{a}  =145.96^0

Both of these make a valid triangle with A=20°.   They give respective B's:

B_{a}=180-A-C_{a}  =125.96^0

B_{0}=180-C_{0}  =14.033^0

So we get two possibilities for b:

b=\frac{asinB}{sinA} \\\\b_{a} =\frac{3.3sin125.96}{sin 20} \\\\b_{a}=7.8\\\\ b_0=2.3

2.3 units and 7.8 units

Therefore we get the length 2.3 and 7.8 units

To learn more about the low of sine and cosine visit:

brainly.com/question/4372174

Answer: 2.3 units and 7.8 units

Let's check it with the Law of Cosines:

There's a shortcut for the quadratic formula when the middle term is 'even.'

Looks good.

4 0
2 years ago
An ellipse has vertices of (5, 0) and (–5, 0) and covertices of (0, 2) and (0, –2). Use the given information to answer the ques
ValentinkaMS [17]

Answer:

The line the foci will be graphed is?

y=0

The foci are located at about ?

(4.58, 0) and (-4.58, 0)

What type of lines will the directrices be?

Both vertical

The directrices are located at about?

x= 5.46 and x= -5.46

Step-by-step explanation:

7 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Ne4ueva [31]
Slope of AD = (2k - 0)/(2j -b - 0) = 2k/(2j - b)
slope of BC = (2k - 0)/(2j - b) = 2k / (2j - b)
AD ║ BC (same slope)

Slope of AB = 0
Slope of DC = 0

AB║DC

7 0
3 years ago
Read 2 more answers
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