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Dennis_Churaev [7]

2 years ago

11

An arc spans a central angle that is \dfrac{3\pi}{5}

1 answer:

Jobisdone [24]2 years ago

7 0

Answer:

what does \dfrac mean

Step-by-step explanation:

I'm only in 11th grade and I don't know anything of this cuz I'm dum

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Can someone please answer this correct?

lidiya [134]

Answer:

A: choice 2, then choice 3

B: No

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas

iren [92.7K]

For the last part, you have to find where $f'(t)$ attains its maximum over $0\le t\le8$ . We have

$f'(t)=-6\sin3t+6\cos2t$

so that

$f''(t)=-18\cos3t-12\sin2t$

with critical points at $t$ such that

$-18\cos3t-12\sin2t=0$

$3\cos3t+2\sin2t=0$

$3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0$

$\cos t(3\cos^2t-9\sin^2t+4\sin t)=0$

$\cos t(12\sin^2t-4\sin t-3)=0$

So either

$\cos t=0\implies t=\dfrac{(2n+1)\pi}2$

or

$12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi$

where $n$ is any integer. We get 8 solutions over the given interval with $n=0,1,2$ from the first set of solutions, $n=0,1$ from the set of solutions where $\sin t=\dfrac{1+\sqrt{10}}6$ , and $n=1$ from the set of solutions where $\sin t=\dfrac{1-\sqrt{10}}6$ . They are approximately

$\dfrac\pi2\approx2$

$\dfrac{3\pi}2\approx5$

$\dfrac{5\pi}2\approx8$

$\sin^{-1}\dfrac{1+\sqrt{10}}6\approx1$

$2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7$

$2\pi+\sin^{-1}\dfrac{1-\sqrt{10}}6\approx6$

4 0

3 years ago

2^3+5x(6+4)÷2, for MATH LIB

Lynna [10]

Evaluate 2^3+5x(6+4)÷2 following Order of Operations rules (PEMDAS):

Work within parentheses is done first, followed by exponentiation, and then mult. and div., and finally add'n. and subtr'n.

Thus, 2^3+5x(6+4)÷2 becomes 2^3+5x(10)÷2

8 + 50x/2

8 + 25x

3 0

3 years ago

Prej drove 34.8 miles on Friday, 71.15 miles on

AfilCa [17]

Answer:

146.85

Step-by-step explanation:

Prej drove 146.85 miles over the 3 day weekend

6 0

4 years ago

A Square Tile has the area of 49 square inches what is the length of these tiles

Kruka [31]

Area = Length x Length

Length = √49 = 7 inches

Answer: 7 inches

6 0

4 years ago