Question

One gram of a certain health food contains 7 percent of the minimum daily requirement of vitamin E and 3 percent of the minimum daily requirement of vitamin A. If vitamins E and A are to be obtained from no other source, approximately how many grams of the health food must be eaten daily to provide at least the minimum daily requirement of both vitamins?

Answer 1

Answer:

Approximately 34 grams of the healthy food

Step-by-step explanation:

For know the minimum value to be eaten daily to provide the requirement of both vitamins, is necessary to calculate the minimum value for every vitamin, so:

• vitamin E: We are going to use the rule of three in which 1 gram have 7% of the minimum daily requirement, then how many grams are going to be be the 100% of the daily requirement:

1 gram --------------7%

X grams -----------100%

$X=\frac{1 gram* 100}{ 7 } = 14.285 grams$

So, it is necessary approximately 15 grams of healthy food to complete th 100% of the minimum daily requirement of vitamin E.

• vitamin A: We are going to use the rule of three in which 1 gram have 3% of the minimum daily requirement, then how many grams are going to be be the 100% of the daily requirement:

1 gram --------------3%

X grams -----------100%

$X=\frac{1 gram* 100}{ 3 } = 33.33 grams$

So, it is necessary approximately 34 grams of healthy food to complete th 100% of the minimum daily requirement of vitamin E.

Finally for satisfy with both minimum daily requirement, we need to eat at least 34 grams of healthy food, because it is the maximum between the two X values.