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frosja888 [35]
2 years ago
6

Please determine the conjugate of 9 - 3i ?

Mathematics
2 answers:
Kazeer [188]2 years ago
7 0

Step-by-step explanation:

You find the complex conjugate simply by changing the sign of the imaginary part of the complex number.

the answer is

9+3i

swat322 years ago
5 0

Answer:

9 + 3i

Step-by-step explanation:

The conjugate is just the opposite so a+b is a-b in this scenario 9 - 3i has a conjugate of 9 + 3i

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In Twila's class, there are 20 students. of the students are boys. How many of the students in her class are boys
Dvinal [7]

Answer:

set your question well

and I will answer it

Step-by-step explanation:

5 0
3 years ago
What is the ratio of 96:132 in simplest form?
Aleks04 [339]
Treat ast fraction
96/132
divide by 2,3,5,7 or factors starting from 2
96/2=48
132/2=66

48/66
divide 2
48/2=24
66/2=33

24/33
divide 3 since cannot divide 33 by 2
24/3=8
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8:11
answer is 8:11
4 0
3 years ago
Read 2 more answers
Selena's favorite chocolate chip cookie recipe calls for 111 teaspoon of salt for every {2 \dfrac{1}{4}}2
NeTakaya

Answer:

It is deepak's just trust me

Step-by-step explanation:

7 0
3 years ago
I'll. ark brainlyest and give a lot of points for answering this right ​
valina [46]

Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

\displaystyle S' ( 3,2)

Step-by-step explanation:

we current vertices of the given triangle

  • \displaystyle T( - 2,4)
  • \displaystyle U( - 1,1)
  • \displaystyle S ( - 3,2)

remember that,

\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \:  over \: y - axis}( -  x,y)

so we obtain:

\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \:  over \: y - axis}T'(  2,4)

\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \:  over \: y - axis}U' ( 1,1)

\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \:  over \: y - axis}S'( 3,2)

6 0
3 years ago
Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina com 1mx0,8m. Sabendo que ele recortou 2 triângulos, a
Gnom [1K]

Answer:

7190 cm²

Step-by-step explanation:

Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina de 1 m x 0,8m.

Passo 1

Determine a área de todo o papelão

= Temos dimensões = 1mx0,8m

Área = Comprimento × Largura

= 0,8m²

Nós convertemos para cm²

1 m² = 10.000 cm²

0,8m² = x cm²

Multiplicação cruzada

0,8m² × 10.000 cm² / 1 m²

= 8000 cm²

Passo 2

Sabendo que recortou 2 triângulos, ambos com 20cm de base e 30cm de altura

Encontramos a área de um triângulo

= 1/2 × base × altura

= 1/2 × 20 × 30

= 300cm²

Ele cortou 2 triângulos Portanto, o são dos dois triângulos = 300cm² × 2

= 600cm²

etapa 3

Ele também cortou 2 trapézios ambos com bases de 10cm e 20cm e altura de 7cm.

A área de um trapézio =

1/2 (a + b) h

= 1/2 (10cm + 20cm) × 7cm

= 1/2 × 30 × 7

= 105 cm²

Ele cortou dois trapézios, portanto

A área dos dois trapézios do corte = 105cm² × 2

= 210 cm²

Passo 4

A área total do papelão que foi cortado = 600cm² + 210cm²

= 810 cm²

Etapa 5

Determine em cm² quanto de papelão sobrou.

Isso é calculado como:

Área total do papelão - Área total que foi cortada

= 8000 cm² - 810 cm²

= 7190 cm²

5 0
3 years ago
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