10.44yd
a^2 + b^2 = c^2
3^2 + 10^2 = c^2
109 = c^2
C (Hypotenuse) ≈ 10.44
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.
f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
Answer:
Method 1:
Find the Least Common Denominator (LCD) of all the denominators in the complex fractions.
Multiply this LCD to the numerator and denominator of the complex fraction.
Simplify, if necessary.
Method 2:
Create a single fraction in the numerator and denominator.
Apply the division rule of fractions by multiplying the numerator by the reciprocal or inverse of the denominator.
Simplify, if necessary.
The given equations are
12x + 4y = 152 ...........1
32x + 12y = 420 .....2
Multiplying equation 1 by 3 to make coefficient of y same we have:
36x+12y= 456
32x+12y=420
Subtracting the two equations we have:
4x=36.
Dividing by 4 both sides
x= 9.
Substituting x value in equation 1
12(9) + 4y = 152
108+4y=152
Subtracting 108 both sides: 4y=44.
Dividing both sides by 4.
y=11.
cost of the vegetarian lunch is $11.
In the equations, x represents the cost of a chicken lunch and y represents the cost of a vegetarian lunch.
