Determine the constant rate of change (slope) of the linear function.
2 answers:
Answer:
A customer pays $12,975.00 for a $8,600.00 bill. Find the least amount of bills and coins to give change.
First calculate change amount
Change = Cash - Bill
Change = $12,975.00 - $8,600.00
Change = $4,375.00
Next calculate denominations and quantities of change that get us to 0
Our current target value is $4,375.00
The highest coin/dollar value <= $4,375.00 is 43 hundred-dollar bills
43 hundred-dollar bills = $4,300.00
Subtract $4,300.00 from our current total of $4,375.00 to get $75.00
Our current target value is $75.00
The highest coin/dollar value <= $75.00 is 1 fifty-dollar bill
1 fifty-dollar bill = $50.00
Subtract $50.00 from our current total of $75.00 to get $25.00
Our current target value is $25.00
The highest coin/dollar value <= $25.00 is 1 twenty-dollar bill
1 twenty-dollar bill = $20.00
Subtract $20.00 from our current total of $25.00 to get $5.00
Our current target value is $5.00
The highest coin/dollar value <= $5.00 is 1 five-dollar bill
1 five-dollar bill = $5.00
Subtract $5.00 from our current total of $5.00 to get $0.00
Step-by-step explanation:
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The data are reported in the attached table.
We define the null hypothesis H₀ as the statement that is believed true until we prove it wrong with the test.
We define the alternative hypothesis H₁ as the statement we want to conclude with our test.
The difference in graffiti before (B) and after (A) will be:
d = A - B.
If the graffiti declined, it means that A will be smaller than B, therefore d should be negative.
Therefore we can set:
H₀ : μd ≥ 0
H₁ : μd < 0
The equal sign would mean that the number of graffiti incidents remained constant, therefore it is part of the null hypothesis.
Therefore the correct answer is B) H₀: μd ≥ 0 versus <span>H₁</span>: μd < 0
We define the null hypothesis H₀ as the statement that is believed true until we prove it wrong with the test.
We define the alternative hypothesis H₁ as the statement we want to conclude with our test.
The difference in graffiti before (B) and after (A) will be:
d = A - B.
If the graffiti declined, it means that A will be smaller than B, therefore d should be negative.
Therefore we can set:
H₀ : μd ≥ 0
H₁ : μd < 0
The equal sign would mean that the number of graffiti incidents remained constant, therefore it is part of the null hypothesis.
Therefore the correct answer is B) H₀: μd ≥ 0 versus <span>H₁</span>: μd < 0