The answer is C because magnitude (-5) is (5) which >0
Q=number of quarters
d=number of dimes
so the value of 1 quarter=0.25 and 1 dime=0.10 so therefor the total value would be
0.25q+0.1d=2.9
total number of coins=20
q+d=20
solve
we have
0.25q+0.1d=2.9 and
q+d=20
multiply the first equation by 10
2.5q+1d=29
so we have
q+d=20
2.5q+d=29
multiply first by -1 and add
-q-d=-20
<u>2.5q+d=29 +
</u>1.5q+0d=9
1.5q=9
multipliy both sides by 2
3q=18
divide by 3
q=6
subsitute
q+d=20
6+d=20
ubtract 6
d=14
14 dimes
6 quarters
<u />
We know that
sin(A + B) = sin A cos B + cos A sin B----> equation 1
sin(A − B) = sin A cos B − cos A sin<span> B----> equation 2
so
</span>tan A+tan B=[sin A/cos A]+[sin B/cos B]
=[(cos B*sin A)+(sin B*cos A)](cos A*cos B)
substitute equation 1
sin (A+B)/(cos A*cos B)
tan A-tan B=[sin A/cos A]-[sin B/cos B]
=[(cos B*sin A)-(sin B*cos A)](cos A*cos B)
substitute equation 2
sin (A-B)/(cos A*cos B)
[tan A+tan B]/[tan A-tan B]
=[sin (A+B)/(cos A*cos B)]/[sin (A-B)/(cos A*cos B)]
=[sin (A+B)/sin (A-B)]
hence
[tan A+tan B]/[tan A-tan B]=[sin (A+B)/sin (A-B)]
Answer:
Multiply 1xm plus -4 plus 23m which gives you the answer
Step-by-step explanation: