Based on the calculations, the equation of this parabola is equal to (x - 6)² = 16(y + 4).
<h3>How to determine the equation of this parabola?</h3>
Mathematically, the standard equation with the vertex for a parabola is given by:
(y - k)² = 4a(x - h) for horizontal parabola.
(x - h)² = 4a(y - k) for vertical parabola.
<u>where:</u>
By critically observing the points, we can deduce that both the focus and vertex lie on the same vertical line x = 6.
<u>Given the following data:</u>
Focus with points = (6, 2).
Vertex (h, k) = (6, –4).
<u>Note:</u> a = 2 - (-4) = 2 + 4 = 6.
Substituting the given parameters into the formula, we have;
(x - 6)² = 4 × 4(y - (-4))
(x - 6)² = 16(y + 4).
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Constructing an a circle inscribed in a triangle involves these steps:
i) Draw 2 (or 3) of the angle bisectors. Their point of intersection is the center of the inscribed circle, or the incenter. Let's denote this point by O
ii) Draw a perpendicular line segment from the incenter to one of the sides. Let the intersection of the perpendicular from O and the side be T.
iii) Draw a circle with center the incenter, and radius the distance OT.
Answer: B) Only perpendicular bisectors are not involved.
#1<span> Plug equations 4, 5, 6, and 7 into equation 3
To better combine like terms ... rearange the numbers
combine like terms (y's and constants cancel out)
Divide by 5
Plug this back into equations 5 and 7
#2 </span><span>Apply concepts of density based on area and volume in modeling ... Mathematically proficient students can apply the mathematics they know to solve problems arising in ... In Grade 3, students used modeling to solve real-world problems involving perimeter of polygons.
#3 </span><span>D Ira built his model using cross sections that were cut parallel to the base what shape was each cross section
</span>
Answer: 10202
Step-by-step explanation:you are right! I’m pretty sure!
H(3)=10
H(10)=101
H(101)= 10202
Answer:
340-60=?
Step-by-step explanation: