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1 year ago

Factorise fully (please help)

Mathematics

1 answer:

Alona [7]1 year ago

4 0

Answer:

(2ab + 1) • (4a2b2 + 2ab + 1)

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this is the answer I ended up with

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PLS help meeeeeeee!!!!!! will mark as BRAINLIEST

Zolol [24]

We are asked to find 7 is what percent to 30.

We will use proportions to solve our given problem.

Let us assume that 7 is n% of 30. So we can set a proportion as:

$\frac{n}{100}=\frac{7}{30}$

Let us solve for n.

$\frac{n}{100}\cdot 100=\frac{7}{30}\cdot 100$

$n=\frac{7}{3}\cdot 10$

$n=\frac{70}{3}$

$n=23.333$

Therefore, 7 is $23.333\%$ of 30.

3 0

3 years ago

John has 8/9 of a gallon of apple cider vinegar. If it takes 1/7 of a gallon of vinegar to make a batch of collard greens, how m

kumpel [21]

1/7 gallon = 1 batch

[multiply by 7 through]
1 gallon = 7 batches

[multiply by 8/9 through]
8/9 gallon = 7 x 8/9
8/9 gallon = 6 2/9

[Good enough to make 6 batches, not enough to make 7 batches]

So he can make 6 batches of collard green

5 0

2 years ago

Given that aₙ = (-2) (5)ⁿ⁻1 for a geometric sequence, determine the common ratio:

patriot [66]

Answer:

Step-by-step explanation:

The nth term of the geometric sequence is

$a_n=(-2)(5)^{n-1}$

In general the nth term of a geometric sequence is

$a_n=a_1(r)^{n-1}$

By comparism;

$r=5$ is the common ratio of the sequence.

$a_1=(-2)(5)^{1-1}=-2$

$a_2=(-2)(5)^{2-1}=-10$

Common ratio is

$r=\frac{-10}{-2}=5$

4 0

3 years ago

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan

vitfil [10]

Answer:

$a = 6m/s^2$

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

$a\ \alpha\ \frac{1}{m}$

Convert variation to equality

$a = \frac{F}{m}$ ; Where F is the constant of variation (Force)

Make F the subject of formula;

$F = ma$

When mass = 4kg; Acceleration = 15m/s²

$F = 4 * 15$

$F = 60N$

When mass = 10kg; Substitute 60 for Force

$F = ma$

$60 = 10 * a$

$60 = 10a$

Divide both sides by 10

$\frac{60}{10} = \frac{10a}{10}$

$a = 6m/s^2$

Hence, the acceleration is  $a = 6m/s^2$ 

4 0

3 years ago

a reading teacher recorded the number of pages read in an hour by each of her students. The numbers are shown below: 54,39,29,43

Ilya [14]

Answer: The answer is 29, because that 29 would be the outlier of the numbers.

Step-by-step explanation:

8 0

3 years ago

Factorise fully (please help) ​

Factorise fully (please help)