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1 year ago

. Brad took 5 kicks and made 4 goals:

Mathematics

1 answer:

SOVA2 [1]1 year ago

4 0

Answer: 8

Step-by-step explanation: convert 4/5 to 8/10. 8 out of 10 shots

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Copy the figure below onto a separate sheet of paper. Find the image of the figure under reflections in line m and then line t.

san4es73 [151]

The image of the figure under reflections in line m and then line t is shown below.

<h3>What is a transformation of geometry?</h3>

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Reflection does not change the size and shape of the geometry.

The image of the figure under reflections in line m and then line t.

The reflection of the rectangle DEFG will be given in the figure.

More about the transformation of geometry link is given below.

brainly.com/question/22532832

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2 years ago

Given the diagram below, find the value of x.

Rufina [12.5K]

Answer:

yes 11000

Step-by-step explanation:

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2 years ago

Which equation matches the graph?

DIA [1.3K]

Answer:

y=3x-2

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

To input your angle measures in degrees, use the functions sind, cosd and tand, instead of sin, cos and tan. Zach stands at the

kramer

Answer:

about 2949 feet

Step-by-step explanation:

The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...

Tan = Opposite/Adjacent

<h3>setup</h3>

Filling in the known values, we have ...

tan(6°) = (310 ft)/(distance to coyote)

<h3>solution</h3>

Multiplying by (distance to coyote)/tan(6°) gives ...

distance to coyote = (310 ft)/tan(6°) ≈ 310/0.105104 ft

distance to coyote ≈ 2949.453 ft

The coyote is about 2949 feet from the base of the cliff.

6 0

2 years ago

Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

6 0

3 years ago