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(this is me adding characters)
<span>given:
bull's eye radius= x
width of surrounding rings=y
solution:
Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring
=Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
=Ď€(2xy+7y^2)
hence the area of the outermost ring in terms of x and y is π(2xy+7y^2).</span>
<em>Greetings from Brasil...</em>
First degree equation. The variables are in the 1st member and the numbers in the 2nd member.
X + 6 - 2X = X - 24
X - 2X - X = - 24 - 6
- 2X = - 30
<h2>X = 15</h2>
