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JulsSmile [24]
2 years ago
14

If f (x) = 8(5x-2) find f -1 (x).

Mathematics
1 answer:
saw5 [17]2 years ago
6 0

Step-by-step explanation:

f(x)=8(5x-2)

interchanging the role of x&y

x=8(5y-2)

  • x=40y-16
  • x+16=401y
  • y=(x+16)/40

f-1(x)=(x+16)/10

<h3>stay safe healthy and happy.</h3>
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David and Rob each got the same-size pack of crackers. David
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Answer: Rob ate more crackers.

Symbol answer: 6/12 < 9/12

Step-by-Step explanation:

Common knowledge: Anytime you have the same numerator, with a different denominator, the one with the bigger denominator is always smaller. For example, if had a pizza with 6 slices and a pizza with 4 slices, the one with 6 slices and smaller and the one with 4 slices and bigger. Even though 6>4 that mindset has to change when thinking about a problem like this.

<em>Another explanation: </em>

<em>If you still don’t get it, simply find a common denominator, so we’ll choose 12. Take 3/6 and multiply that by 2/2 so you get 6/12 and then take 3/4 and multiply that by 3/3 on both the (numerator and denominator) and that equals 9/12.</em>

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For the system of equations that follows, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in
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Answer:

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Step-by-step explanation:

From the question we are told that

System of equations given as

x₁ + 3x₂ + x₃ + x₄ = 3;

2x₁ - 2x₂ + x₃ + 2x₄ = 8;

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Matrix form

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}  \begin{Vmatrix}x_1\\x_2\\x_3\\x_4\end{Vmatrix}

Generally the echelon reduction is mathematically applied as

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -2 times the 1st row to the 2nd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & -8 & -1&0&2\\0&1 & -5 & 1& 5\end{Vmatrix}

Multiply the 2nd row by -1/8  

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -1 times the 2nd row to the 3rd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & -41/8 & 1& 21/4\end{Vmatrix}

Multiply the 3rd row by -8/41

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -1/8 times the 3rd row to the 2nd row

Add -1 times the 3rd row to the 1st row

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Add -3 times the 2nd row to the 1st row

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

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