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Vinil7 [7]
2 years ago
14

Find the product. (n 7)2 n² 14n 14 2n² 14n 49 n² 14n 49.

Mathematics
1 answer:
Marianna [84]2 years ago
8 0

The product of \rm (n+7)^2 is \rm n^2+14n+49.

Given

The product of \rm (n+7)^2.

<h3>What is multiplication?</h3>

Multiplication is the process of calculating the product of two or more numbers.

The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.

The product of \rm (n+7)^2 is given by;

\rm =(n+7)^2\\\\=(n+7)\times (n+7)\\\\= n(n+7)+7(n+7)\\\\=n^2+7n+7n+49\\\\=n^2+14n+49

Hence, the product of \rm (n+7)^2 is \rm n^2+14n+49.

To know more about Multiplication click the link given below.

brainly.com/question/19943359

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Answer:

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My question is y = 4x + 1 and my options are<br>a. 4, 3 <br>b. 4,1<br>c. 1,4<br>d. 3,1​
Akimi4 [234]

Answer:

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Step-by-step explanation:

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bazaltina [42]

We have the equation:

x^2+y^2-8x-6y+24=0


By arranging this equation in terms of x and y, we have:


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x^2-8x+\mathbf{\left(\frac{8}{2}\right)^2}+y^2-6y+\mathbf{\left(\frac{6}{2}\right)^2}=-24+\mathbf{\left(\frac{8}{2}\right)^2}+\mathbf{\left(\frac{6}{2}\right)^2} \\ \\ x^2-8x+\mathbf{16}+y^2-6y+\mathbf{9}=-24+\mathbf{16}+\mathbf{9} \\ \\ \boxed{(x-4)^2+(x-3)^2=1}


The center of this circle is:

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6 0
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2.  let x = length of the rpoe)-

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Kruka [31]

Answer:

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1 year ago
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