9514 1404 393
Answer:
(c) f(x) is an even degree polynomial with a positive leading coefficient.
Step-by-step explanation:
The leading terms of the two functions are ...
f(x): x² (even degree, positive coefficient: 1)
g(x): x³ (odd degree, positive coefficient: 1)
Then it is true that ...
f(x) is an even degree polynomial with a positive leading coefficient
Answer:
y - 2 = - 5(x - 7)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = - 5 and (a, b) = (7, 2) , thus
y - 2 = - 5(x - 7) ← equation in point- slope form
Answer:
28m⁷n⁵
Step-by-step explanation:
You would first multiply 14 by 2. You would then multiply (which is really addition when it comes to exponents) your like-term exponents.
(14m²n⁵)(2m⁵) =28m⁷n⁵
14(2) = 28
m² + m⁵=m⁷
n⁵ + 0 = n⁵
Using derivatives, it is found that regarding the tangent line to the function, we have that:
- The equation of the line is y = 962x - 5119.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
The slope of the line tangent to a function f(x) at x = x' is given by f'(x'). In this problem, the function is given by:
f(x) = 5x³ + 2x + 1.
The derivative is given by:
f'(x) = 15x² + 2.
Hence the slope at x = 8 is:
m = f'(8) = 15(8)² + 2 = 962.
The line goes through the point (8,f(8)), hence:
f(8) = 5(8)³ + 2(8) + 1 = 2577.
Hence:
y = 962x + b
2577 = 962(8) + b
b = -5119.
Hence the equation is:
y = 962x - 5119.
More can be learned about tangent lines at brainly.com/question/8174665
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Answer:your question seems incomplete but if you looking to find the resulting equation to solve for temperature at a particular time you can use this 28t^2
Step-by-step explanation:
F'(t) = 7(0.8)t
Integrating the RHS
Temp= integral of f'(t)= 28t^2
Therefore, T(°c)= 28t^2
