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zhannawk [14.2K]
3 years ago
12

Determine the common ratio and find the next three terms of the geometric sequence t8, t5, t2

Mathematics
2 answers:
Charra [1.4K]3 years ago
5 0
T^5/t^8=t^(5-8)=t^(-3)
t^2/t^5=t^(2-5)=t^(-3)

The common ratio is t^(-3)

The next three terms are:
t^2*t^(-3)=t^(2-3)=t^(-1)
t^(-1)*t^(-3)=t^(-1-3)=t^(-4)
t^(-4)*t^(-3)=t^(-4-3)=t^(-7)

Answer: The next three terms of the geometric sequence t^8, t^5, t^2 are:
t^(-1), t^(-4), t^(-7)
attashe74 [19]3 years ago
3 0
The common ratio of the given geometric sequence is the number that is multiplied to the first term in order to get the second term. Consequently, this is also the number multiplied to the second term to get the third term. This cycle goes on and on until a certain term is acquired. In this item, the common ratio r is,

    r = t⁵/t⁸ = t²/t⁵

The answer, r = t⁻³.

The next three terms are,

    n₄ = (t²)(t⁻³) = t⁻¹
    n₅ = (t⁻¹)(t⁻³) = t⁻⁴
    n₆ = (t⁻⁴)(t⁻³) = t⁻⁷

The answers for the next three terms are as reflected above as n₄, n₅, and n₆, respectively. 
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Answer:

See Below

Step-by-step explanation:

<u>Statements:</u>                                                        <u>Reasons:</u>

<u />1)\text{ } \Delta PQR\text{ is equilateral}                                        Given

2)\text{ }PQ=QR=RP                                               Definition of Equilateral

3)\text{ } X, Y, Z\text{ are the midpoints of } PQ, QR, RP       Given

4)\text{ } PX=XQ                                                        Definition of Midpoint

5)PQ=PX+XQ                                               Segment Addition

6)\text{ } PQ=2XQ                                                      Substitution

7)\text{ } QY=YR                                                        Definition of Midpoint

8)\text{ }QR=QY+YR                                               Segment Addition

9)\text{ } QR=2QY                                                       Substitution

10)\text{ } 2XQ=2QY                                                  Substitution

11)\text{ } XQ=QY                                                      Division Property of Equality

12)\text{ }  XQ=PX=QY=YR                                Transitive Property

13)\text{ } RZ=ZP                                                       Definition of Midpoint

14)\text{ } RP=RZ+ZP                                             Segment Addition

15)\text{ } RP=2RZ                                                     Substitution

16)\text{ } 2XQ=2RZ                                                   Substitution

17)\text{ } XQ=RZ                                                       Substitution

18)\text{ } XQ=PX=QY=YR=RZ=ZP            Transitive Property

19)\text{ } \angle Q\cong \angle R\cong \angle P                                             Definition of Equilateral

20)\text{ } \Delta XQY\cong \Delta YRQ \cong \Delta ZPX                          SAS Congruence

21)\text{ } XY\cong YZ\cong ZX                                           CPCTC

22)\text{ } \Delta XYZ\text{ is equilateral}                                     Equilateral Triangle Theorem

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2 years ago
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