The interest paid is Rs 10000
The rate of interest is 20%
Step-by-step explanation:
Step 1 :
Amount borrowed by Mr. Satyal = Rs 50000
Amount repaid = Rs 60000
Interest is charged on the principal amount and the amount repaid will be the sum of the interest paid plus the principal amount
Hence the interest paid is 60000 - 50000 = Rs 10000
Step 2:
The rate of interest is calculated as follows :
Divide the interest calculated by the principal amount and is expressed as percentage.
Hence the interest rate = 
× 100 = 20%
Step 3 :
The interest paid is Rs 10000
The interest rate is 20%
Answer:
B. $3100
Step-by-step explanation:
if he's going to pay for his friend. The least expensive dinner menu is $725, for him and his friend it would be $1450. Then for the movie tickets it's $8.00 each, $16.00. $1450+$16.00=$30.50. Round that to the closest whole number, $3100.
The lines are
i) y=-x+6
ii) y=2x-3
The solution of the system of equations is found by equalizing the 2 equations:
-x+6=2x-3
-2x-x=-6-3
-3x=-9
x=-9/(-3)=3
substitute x=3 in either i) or ii):
i) y=-3+6=3
ii) y=2(3)-3=6-3=3
(the result is the same, so checking one is enough)
This means that the point (3, 3) is a point which is in both lines, so a solution to the system.
In graphs, this means that the lines intersect at (3, 3) ONLY
Answer: The graph where the lines intersect at (3, 3)
Answer:
0.6 seconds to 2.6 seconds
Step-by-step explanation:
From the graph the ball reaches 28 feet after 0.574 seconds
and doesn't fall below that until 2.614 seconds
0.574 rounded is 0.6 seconds
2.614 rounded is 2.6 seconds
Answer:
The probability that the control chart would exhibit lack of control by at least the third point plotted is P=0.948.
Step-by-step explanation:
We consider "lack of control by at least the third point plotted" if at least one of the three first points is over the UCL or under the LCL.
The probability of one point of being over UCL=104 is:
The probability of one point of being under LCL=96 is:
Then, the probability of exhibit lack of control is:
The probability of having at least one point out of control in the first three points is:
The probability that the control chart would exhibit lack of control by at least the third point plotted is P=0.948.
