Hey there!
To find the equation of a line, we first have to determine its slope knowing that parallel lines have the same slope.
Let the line that we are trying to determine its equation be 
and the line that is parallel to be 
.
passes through the points (9 , 2) and (3 , -5) which means that we can find its slope using the slope formula:
⇒Subtitute the values :
.
Assuming that we want to get the equation in Slope-Intercept Form, let's substitute m = 7/6:
Slope-Intercept Form:
We know that the coordinates of the point (0 , -3) verify the equation since it is on the line . Now, replace y with -3 and x with 0:
Therefore, the equation of the line 
is 
▪️Learn more about finding the equation of a line that is parallel to another one here:
↣brainly.com/question/27497166
Answer: 70 meters
Step-by-step explanation:
Hi, since the situation forms a right triangle and a rectangle, we have to apply the Pythagorean Theorem (for the triangle)
c^2 = a^2 + b^2
Where c is the hypotenuse of the triangle (the longest side) and a and b are the other sides.
Replacing with the values given:
65^2 = 16^2 + x^2
4,225 = 256 + x^2
4,225-256 = x^2
3,969=x^2
√3,969 =x
63=x
We have calculated the missing side of the triangle, now we have to add the height of the rectangle:
63 +7 =70 meters
Feel free to ask for more if needed or if you did not understand something.
Take the linear coefients easy
11,-12, 7
5,12,-7
so
![\left[\begin{array}{ccc}11&-12&7\\5&12&-7\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%26-12%267%5C%5C5%2612%26-7%5Cend%7Barray%7D%5Cright%5D%20)
or you could do also
![\left[\begin{array}{ccc}11&-12\\5&12\end{array}\right] \left[\begin{array}{ccc}7\\-7\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%26-12%5C%5C5%2612%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%5C%5C-7%5Cend%7Barray%7D%5Cright%5D%20)
I could be wrong but I’m pretty sure x≈102.2 and y≈58
