9514 1404 393
Answer:
"and"
Step-by-step explanation:
Properly written, the word "and" separates the integer portion from the fractional portion of the number. If there is no "and", then there is no integer portion, so the number is a fraction less than 1.
<u>Examples</u>:
one <em>and</em> three tenths = 1 3/10
thirty-one thousandths = 31/1000
1500 ice cubes need to fill 1.5 L jar
Solution:
1 cm = 1 ml
Capacity of ice cube = 1 cm
= 1 ml
Capacity of jar = 1.5 L
1 L = 1000 ml
1.5 L = 1.5 × 1000
= 1500 ml
Capacity of jar = 1500 ml
= 1500
Therefore 1500 ice cubes need to fill 1.5 L jar.
Answer:
10.2% of adults will belong to health clubs and will go to the club at least twice a week
Step-by-step explanation:
assuming that the event H=an adult belongs to a health club and the event T= he/she goes at least twice a week , then if both are independent of each other:
P(T∩H)= P(H)*P(T) ( probability of the union of independent events → multiplication rule )
replacing values
P(T∩H)= P(H)*P(T) = 0.20 * 0.51 =0.102
then 10.2% of adults will belong to health clubs and will go to the club at least twice a week
Let's say we wanted to subtract these measurements.
We can do the calculation exactly:
45.367 - 43.43 = 1.937
But let's take the idea that measurements were rounded to that last decimal place.
So 45.367 might be as small as 45.3665 or as large as 45.3675.
Similarly 43.43 might be as small as 43.425 or as large as 43.435.
So our difference may be as large as
45.3675 - 43.425 = 1.9425
or as small as
45.3665 - 43.435 = 1.9315
If we express our answer as 1.937 that means we're saying the true measurement is between 1.9365 and 1.9375. Since we determined our true measurement was between 1.9313 and 1.9425, the measurement with more digits overestimates the accuracy.
The usual rule is to when we add or subtract to express the result to the accuracy our least accurate measurement, here two decimal places.
We get 1.94 so an imputed range between 1.935 and 1.945. Our actual range doesn't exactly line up with this, so we're only approximating the error, but the approximate inaccuracy is maintained.
Answer:
it's on goggle
Step-by-step explanation:
goggle yeah yeah yeah
