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Over [174]
3 years ago
8

How do I solve this question?

Mathematics
2 answers:
Gre4nikov [31]3 years ago
4 0

Jennifer has the faster training speed, just plug he numbers in.

Vanyuwa [196]3 years ago
3 0
Jennifer is faster just look at the numbers and plug them in
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-2(8m+8)=-16 what is my answer
Vitek1552 [10]

Answer:

m=0

Step-by-step explanation:

4 0
3 years ago
A k out of n system is one in which there is a group of n components, and the system will function if at least k of the componen
kotykmax [81]

Answer:

bbb

St  bep-by-step explanation:

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8 0
3 years ago
Find the distance CD rounded to the nearest tenth<br> C=(10,-1) and D=(-6,3)
Fynjy0 [20]

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

point C can be info set 1: (10, -1)    x₁ = 10   y₁ = -1

point D can be info set 2: (-6, 3)    x₂ = -6  y₂ = 3

Substitute the information into the formula

L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }    Simplify inside each bracket

CD = \sqrt{(-16)^{2}+(4)^{2} }    Square the numbers

CD = \sqrt{256+16 }     Add inside the root

CD = \sqrt{272}    Enter into calculator

CD = 16.5  Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.

4 0
4 years ago
Can someone help me on problems 9, 10 and 11 please!!!
Rasek [7]
9. You shouldn't agree, because they are equal to one another.

10. 84 cents plus 61 should be $1.45 because 84 + 61 is 145 and 100 cents equals 1 dollar, and then you have 45 left over.

100 - .63 is .37 because the whole painting is equal to 1, or .1, or in this case I used it as 100. The drawing is up to you, but you can just draw a canvas and shade in a little bit more than half but not the full canvas. .37 of the canvas is left.
7 0
3 years ago
Read 2 more answers
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
4 years ago
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