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3 years ago

7

Find the coordinates of the intersection of the diagonals of parallelogram QRST with vertices Q(−8, 1), R(2, 1), S(4,−3), and T(

−6,−3).

1 answer:

FinnZ [79.3K]3 years ago

6 0

Answer:

(-2,1)

Step-by-step explanation:

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Please help me with this!!

nydimaria [60]

Answer:

Step-by-step explanation:

these triangles are not similar, you can tell, b/c the one given angle and that they are both right triangles, so you also know that the other angle , that is not given is not the same, in the two. hence the sides are not the same lengths or ratios of each other. they are NA

6 0

2 years ago

What is a comparison of numbers or variables that can be written in fraction form

frozen [14]

I believe
4 and 6
4/1 and 6/1<span />

3 0

3 years ago

(a) Starting with the geometric series [infinity] xn n = 0 , find the sum of the series [infinity] nxn − 1 n = 1 , |x| < 1.

Mila [183]

Let <em>f(x)</em> be the sum of the geometric series,

$f(x)=\displaystyle\frac1{1-x} = \sum_{n=0}^\infty x^n$

for |<em>x</em>| < 1. Then taking the derivative gives the desired sum,

$f'(x)=\displaystyle\boxed{\dfrac1{(1-x)^2}} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1}$

5 0

2 years ago

1-2m-5m=15 multistep homework

Montano1993 [528]

1-2m-5m=15

combine like terms

1 -7m = 15

subtract 1 from each side

1-1-7m = 15-1

simplify

-7m = 14

divide by -7

-7m/-7 = 14/-7

simplify

m = -2

6 0

3 years ago

5,5,3 Is this a triangle? Explain.

Vlad1618 [11]

Problem 1

Answer: <u>Yes</u> a triangle can be formed with side lengths 5,5,3

--------------------

Explanation:

Take any two sides and add them up. If we get a sum larger than the third side, then a triangle is possible. This is the triangle inequality theorem.

5+5 = 10 is larger than 3

5+3 = 8 is larger than 5

This shows a triangle is possible. The triangle is isosceles because two sides are the same length.

==========================================================

Problem 2

Answer: <u>Yes</u> a triangle can be formed with side lengths 8,8,8

--------------------

Explanation:

This triangle is equilateral because all sides are the same length.

Take any two sides, add them up, and you'll find the sum is larger than the third side.

==========================================================

Problem 3

Answer: <u>No</u> a triangle cannot be formed with sides 7,8,15

--------------------

Explanation:

Yes it is true that

8+15 = 23 is larger than 7

7+15 = 22 is larger than 8

but

7+8 = 15 is not larger than 15

So this means a triangle is not possible.

Imagine you had 3 strips of paper that were 7 inches, 8 inches and 15 inches long. The 7 and 8 inch strips add to 15 inches, but those two smaller strips only form a straight line. We cannot pull them so a triangle forms. If we did, then the third side would be smaller than 15 inches. This is one way to get hands on to see why the triangle inequality theorem works.

==========================================================

Problem 4

Answer: <u>Yes</u> a triangle is possible with side lengths 5,6,10

--------------------

Explanation:

Same idea as before. We can take any two sides, add them, and get a sum larger than the third side. A triangle is possible.

5+6 = 11 is larger than 10
6+10 = 16 is larger than 5
5+10 = 15 is larger than 6

4 0

3 years ago