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VashaNatasha [74]

2 years ago

12

Please help with math!!!!!!!

1 answer:

iVinArrow [24]2 years ago

7 0

Answer:

Step-by-step explanation:

5a. 7 < x

b. 2< 2x

c. 8 > x

d. 3 > x/29

joe = j

christina = c

Aaron = a

j = 3a , c = a-6 total ages is 149

149 = j + c+ a

149 = 3a + a-6 + a

149 = 5a-6

add 6 to both sides

149 + 6 = 5a-6+6

155 = 5a

a = 155/5

a = 31

c = a - 6

c = 31 - 6

c = 25

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luda_lava [24]

When comparing and contrasting, it's always good to think about what your doing it with.
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First, let's look at the definition of both terms:

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8 0

3 years ago

Read 2 more answers

PLEASE help me!!!

densk [106]

Answer:

Step-by-step explanation:

first

3/10 & 7/10

second

5/9 & 4/9

7 0

3 years ago

The ratio x : 8 is equivalent to the ratio 8 : x^2. What is the value of x?

dimulka [17.4K]

Answer:

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Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Given the sequence 7, 12, 17, 22, ...

abruzzese [7]

Answer:

option D is true.

Step-by-step explanation:

Given the sequence

7, 12, 17, 22, ...

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

Computing the differences of all the adjacent terms

$12-7=5,\:\quad \:17-12=5,\:\quad \:22-17=5$

The difference between all the adjacent terms is the same

so

$d=5$

as

$a_1=7$

Thus, the nth term of the arithmetic sequence will be:

$a_n=5\left(n-1\right)+7$

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7 0

3 years ago

A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th

Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

$y = \frac{340110}{1 + 377e^{-0.259t}}$

Solving (a): 1998

Year 1998 means that:

$t =1998 - 1980$

$t =18$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*18}}$

$y = \frac{340110}{1 + 377e^{-4.662}}$

$y = \frac{340110}{1 + 3.562}$

$y = \frac{340110}{4.562}$

$y = 74553$ --- approximated

Solving (b): 2003

Year 2003 means that:

$t = 2003 - 1980$

$t =23$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*23}}$

$y = \frac{340110}{1 + 377e^{-5.957}}$

$y = \frac{340110}{1 + 0.976}$

$y = \frac{340110}{1.976}$

$y = 172120$ --- approximated

Solving (c): 2006

Year 2006 means that:

$t = 2006 - 1980$

$t =26$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*26}}$

$y = \frac{340110}{1 + 377e^{-6.734}}$

$y = \frac{340110}{1 + 0.4485}$

$y = \frac{340110}{1.4485}$

$y = 234802$ --- approximated

3 0

3 years ago