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2 years ago

Please help with math!!!!!!!

Mathematics

1 answer:

iVinArrow [24]2 years ago

7 0

Answer:

Step-by-step explanation:

5a. 7 < x

b. 2< 2x

c. 8 > x

d. 3 > x/29

joe = j

christina = c

Aaron = a

j = 3a , c = a-6 total ages is 149

149 = j + c+ a

149 = 3a + a-6 + a

149 = 5a-6

add 6 to both sides

149 + 6 = 5a-6+6

155 = 5a

a = 155/5

a = 31

c = a - 6

c = 31 - 6

c = 25

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ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

ryzh [129]

Answer:

The third option is correct.

The domain of the function is given by

$Domain = 0 \leq t \leq 40$

The range of the function is given by

$Range = 0 \leq V(t) \leq 200$

Step-by-step explanation:

Sara bought a cell phone for $200 and its value has decreased at rate of $5 per month.

V(t) is the value of the phone and t is the number of months.

The domain of the function is the possible values of the number of months t.

The domain of the function is given by

$Domain = 0 \leq t \leq 40$

The range of the function is the values of V(t) that we get after substituting the possible values of the number of months t.

The range of the function is given by

$Range = 0 \leq V(t) \leq 200$

When the number of months is t = 0 then the value of the function is maximum V(t) = 200

When the number of months is t = 40 then the value of the function is minimum V(t) = 0

Therefore, the third option is correct.

6 0

3 years ago

How do I do problems 4-6

faltersainse [42]

4-6= -2 what are you having problems understanding I can help

4 0

3 years ago

Given that v=√u*u- 2qs. Make q the subject of the equation. Find the value of q in the equation if v=8, u=12, and s=40

kifflom [539]

Answer:

Step-by-step explanation:

v=√u*u- 2qs

$\sqrt{20}$ x 20 - 2q40 = 8
$2\sqrt{5}$ x 20 - 2q40 = 8
40 $\sqrt{5}$ - 2q40 = 8
- 2q40 = 8 - 40 $\sqrt{5}$
-80q = 8 - 40 $\sqrt{5}$
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3 0

3 years ago

Read 2 more answers

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erik [133]

1. 14:8, 21:12 28:16
2. 10/12 15/18 20/24
5. 5:4
6. No
7. No
8. Yes
9. No
10. 15

5 0

2 years ago

Find the larger of two consecutive integers if the larger is 149 less than twice the smaller.

snow_tiger [21]

Answer:

151

Step-by-step explanation:

Let x = the smaller integer and y = the larger integer.

We have two conditions:

(1) x + 1 = y

(2) y = 2x - 149 Substitute (1) into (2)

x + 1 = 2x - 149 Add 150 to each side

x + 150 = 2x Subtract x from each side

x = 150 Substitute into (1)

150 +1 = y

y = 151

The larger integer is 151.

<em>Check: </em>

(1) 150 + 1 = 151

151 = 151

(2) 151 = 2×150 -149

151 = 300 -149

151 = 151

4 0

3 years ago