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In-s [12.5K]
3 years ago
5

Please help me with this question

Mathematics
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

? umm what is the question

Step-by-step explanation:

You might be interested in
The equation of a circle whose center is at (1,2) and radius is 5 is (x + 1)² + (y + 2)² = 5 (x - 1)² + (y - 2)² = 25 (x - 1)² -
Oksana_A [137]
\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{1}{ h},\stackrel{2}{ k})\qquad \qquad 
radius=\stackrel{5}{ r}
\\\\\\\
(x-1)^2+(y-2)^2=5^2\implies (x-1)^2+(y-2)^2=25
7 0
3 years ago
Read 2 more answers
PLEASE HELP ME!
elena55 [62]

Answer:

hello :

f(x) = -x+0.25

g(x) = x²+3x+2

ــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ

f(-3.5) = 3.75

g(-3.5) = 3.75

ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ

f(-0.5) =0.75

g(-0.5) = 0.75

ــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ

conclusion : answer : A) x = −3.5 and x = −0.5 

Step-by-step explanation:

Hope this helps:)

3 0
3 years ago
Read 2 more answers
Maria's credit card balance is less then -$30. Does Maria owe more then $30 or less then $30?
PSYCHO15rus [73]
She owes more than $30. She owes for the -$30 that we know of, however much over the -$30 she is, and most likely and interest fee as well.
5 0
3 years ago
Streets A and B run parallel to each other. The measure of <3 is 153 degrees. Find the measure of <5
ipn [44]

Given:

\angle3=153^{\circ}\angle3\text{ and }\angle5\text{ are same side interior angles.}\begin{gathered} \angle3+\angle5=180^{\circ} \\ 153+\angle5=180 \\ \angle5=180-153 \\ \angle5=27^{\circ} \end{gathered}

3 0
1 year ago
a system of linear equations is given by the tables. one of the tables is represented by the equation y=-1/3x+7. The equation th
Jet001 [13]

Answer:

1). Other line is, y = \frac{1}{3}x+5

2). Solution of the system is (3, 6)

Step-by-step explanation:

From the table (1),

Let the equation of the line from the given table is,

y - y' = m(x - x')

Where m = slope of the line

(x', y') is a point lying on the line.

Choose two points from the table which lie on the line.

Let the points are (0, 5) and (3, 6)

Slope = m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                 = \frac{5-6}{0-3}

                 = \frac{1}{3}

Therefore, equation of the will be,

y - 5 = \frac{1}{3}(x-0)

y = \frac{1}{3}x+5 -------(1)

Let the other line from the table (2) is,

y - y" = m'(x - x")

Two points taken from this table are (0, 7) and (3, 6)

m' = \frac{7-6}{0-3}

    = -\frac{1}{3}

Equation of the line will be,

y - 7 = -\frac{1}{3}(x-0)

y = -\frac{1}{3}x+7 -------(2)

Therefore, equation of the other line will be, y = \frac{1}{3}x+5

By adding equations (1) and (2),

y + y = -\frac{1}{3}x+\frac{1}{3}x+5+7

2y = 12

y = 6

From equation (1),

6 = \frac{1}{3}x+5

\frac{1}{3}x=7-6

x = 3

Therefore, solution of the system is (3, 6).

6 0
4 years ago
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