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4 years ago

Where would you expect to find extrusive igneous rock?

Physics

2 answers:

LenaWriter [7]4 years ago

7 0

The answer is underground it is made from cooling of magma your welcome

Masja [62]4 years ago

3 0

The extrusive igneous rock is usually found along the ocean floor. These rocks are formed by the cooling off of semi molten fluid of rocks and other solids called as magma which comes out a volcano when it erupts forming a hard surface on earth.

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Un the way to the moon, the Apollo astro-

kherson [118]

Answer:

Distance = 345719139.4[m]; acceleration = 3.33*10^{19} [m/s^2]

Explanation:

We can solve this problem by using Newton's universal gravitation law.

In the attached image we can find a schematic of the locations of the Earth and the moon and that the sum of the distances re plus rm will be equal to the distance given as initial data in the problem rt = 3.84 × 108 m

$r_{e} = distance earth to the astronaut [m].\\r_{m} = distance moon to the astronaut [m]\\r_{t} = total distance = 3.84*10^8[m]$

Now the key to solving this problem is to establish a point of equalisation of both forces, i.e. the point where the Earth pulls the astronaut with the same force as the moon pulls the astronaut.

Mathematically this equals:

$F_{e} = F_{m}\\F_{e} =G*\frac{m_{e} *m_{a}}{r_{e}^{2} } \\$

$F_{m} =G*\frac{m_{m}*m_{a} }{r_{m} ^{2} } \\where:\\G = gravity constant = 6.67*10^{-11}[\frac{N*m^{2} }{kg^{2} } ] \\m_{e}= earth's mass = 5.98*10^{24}[kg]\\ m_{a}= astronaut mass = 100[kg]\\m_{m}= moon's mass = 7.36*10^{22}[kg]$

When we match these equations the masses cancel out as the universal gravitational constant

$G*\frac{m_{e} *m_{a} }{r_{e}^{2} } = G*\frac{m_{m} *m_{a} }{r_{m}^{2} }\\\frac{m_{e} }{r_{e}^{2} } = \frac{m_{m} }{r_{m}^{2} }$

To solve this equation we have to replace the first equation of related with the distances.

$\frac{m_{e} }{r_{e}^{2} } = \frac{m_{m} }{r_{m}^{2} } \\\frac{5.98*10^{24} }{(3.84*10^{8}-r_{m} )^{2} } = \frac{7.36*10^{22} }{r_{m}^{2} }\\81.25*r_{m}^{2}=r_{m}^{2}-768*10^{6}* r_{m}+1.47*10^{17} \\80.25*r_{m}^{2}+768*10^{6}* r_{m}-1.47*10^{17} =0$

Now, we have a second-degree equation, the only way to solve it is by using the formula of the quadratic equation.

$r_{m1,2}=\frac{-b+- \sqrt{b^{2}-4*a*c } }{2*a}\\ where:\\a=80.25\\b=768*10^{6} \\c = -1.47*10^{17} \\replacing:\\r_{m1,2}=\frac{-768*10^{6}+- \sqrt{(768*10^{6})^{2}-4*80.25*(-1.47*10^{17}) } }{2*80.25}\\\\r_{m1}= 38280860.6[m] \\r_{m2}=-2.97*10^{17} [m]$

We work with positive value

rm = 38280860.6[m] = 38280.86[km]

Second part

The distance between the Earth and this point is calculated as follows:

re = 3.84 108 - 38280860.6 = 345719139.4[m]

Now the acceleration can be found as follows:

$a = G*\frac{m_{e} }{r_{e} ^{2} } \\a = 6.67*10^{11} *\frac{5.98*10^{24} }{(345.72*10^{6})^{2} } \\a=3.33*10^{19} [m/s^2]$

6 0

3 years ago

You push a piano 5 meters across the floor with a force of 400 n. how much work have you done?

kobusy [5.1K]

2,000 j(apex)

i hope this was right

3 0

4 years ago

How are sound waves similar to light waves?

Tom [10]

Answer:

Sound and light are similar in that both are forms of energy that travel in waves.

Explanation:

They both have properties of wavelength, freqency and amplitude. ... Sound can only travel through a medium (substance) while light can travel through empty space. Sound is a form of mechanical energy caused by vibrations of matter.

6 0

3 years ago

Read 2 more answers

A 1900kg airplane is flying at an altitude of 510 above the ground. What is the gravitational potential energy in Joules?

Natalija [7]

Answer: 9496200 joules

Explanation:

Gravitational potential energy, GPE is the energy possessed by the moving plane since it moves against gravity.

Thus, GPE = Mass m x Acceleration due to gravity g x Height h

Since Mass = 1900kg

g = 9.8m/s^2

h = 510 metres (units of height is metres)

Thus, GPE = 1900kg x 9.8m/s^2 x 510m

GPE = 9496200 joules

Thus, the gravitational potential energy of the airplane is 9496200 joules

8 0

3 years ago

If a 0.5 kg pair of running shoes would weigh 11.55 Newton’s on Jupiter, what is the strength of gravity there?

OverLord2011 [107]

The weight of an object is given by
$F=mg$
where m is the mass of the object, while g is the strength of the gravity (which corresponds to the gravitational acceleration of the planet).

In our problem, the shoes have a mass of m=0.5 kg, and their weight is F=11.55 N. So, we can re-arrange the previous formula to find the value of g:
$g= \frac{F}{m}= \frac{11.55 N}{0.5 kg}=23.1 N kg^{-1}$
and this is the strength of the gravity on Jupiter's surface.

4 0

3 years ago