Answer:
60 kWh
Explanation:
The computation of the annual energy consumption in KW-h is shown below:
As we know that
1 kw = 1000 w
So, for 1400 W it would be
= 1,400 ÷ 1,000
= 1.4 kW
Now the number of hours it used in a year
= 7 minutes × 365 days ÷ 60 minutes
= 42.58333 hours
So in one year it used
= 1.4 kW × 42.58333
= 59.61 kWh
= 60 kWh
Answer:
Although this question is not complete, I would give a general solution to this kind of problems.
If y(t) describes the position of a body with time such that
y(t) = at^(n) + bt^(m) + C
Then
V(t) = dy(t)/dt = ant^(n-1) + bmt^(m-1)
Explanation:
As an example supplies the position of a particle is given by
y(t) = 4t³- 3t² + 9
V(t) = 4x3t²- 3x2t¹
V(t) = d(t)/dt = 12t² - 6t.
Another example,
If y(t) = 15t³ - 2t² + 30t -80
V(t) = d(t)/dt = 15x3t² - 4t +30 = 45t² + 4t + 30.
Basically, in the equations above the powers of t reduces by one when computing the velocity function from y(t) by differentiation (calculating the derivative of y(t)). The constant term C (9 and 80 in the functions of y(t) in examples 1and 2 above) reduces to zero because the derivative of a constant (and ordinary number without the t attached to it) is always zero.
One last example,
y(t) = 2t^6 -3t²
V(t) = d(t)/dt = 12t^5 - 6t
Answer:
a is the answer I think so
radio waves bc they have the longest wave lenthgs in a magnetic spectrum
No artificial ingredients
i only know that because my mom was vegan for two years
