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N76 [4]
3 years ago
8

Which material is the best heat insulator? metal wood plastic glass

Physics
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer:

Wood

Explanation:

The measure of any material to conduct heat is called its thermal conductivity. The thermal conductivity of metal is very high as compared to insulators and semiconductors.

The thermal conductivity of wood is 0.12-0.04 W/m K. Plastics have thermal conductivity of 0.2 W/m K. The thermal conductivity of fiber glass or foam glass is 0.045 W/m K

Wood is a best heat insulator. This is because, the atoms of wood have much tightly bound electrons.              

Hence, the correct option is (b).                    

OlgaM077 [116]3 years ago
5 0
Of the materials listed wood is the best insulator. It would be the least hot if exposed to similar temperatures.
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The table represents the forces on four objects, with directions.
noname [10]

b. Objects W and Y have balanced forces, and objects X and Z have unbalanced forces.

Explanation:

An object is said to have balanced forces if the resultant of the forces acting on it is zero. This situation occurs, for instance, when the sum of the forces on the vertical direction is zero and the sum of the forces on the horizontal direction is zero as well.

For the objects in the table, we see that:

- Object W: the resultant on the vertical direction is zero, because we have two opposite forces with same magnitude (30 N), so they cancel each other. Also, the resultant on the horizontal direction is zero, because we have two opposite forces with same magnitude (20 N), so they cancel each other.

- Object X: the resultant on the vertical direction is zero, because we have two opposite forces with same magnitude (15 N), so they cancel each other. However, the resultant on the horizontal direction is NOT zero, because we have two opposite forces but with different magnitude (35 N and 25 N), so they do not cancel each other, and they make a net force of 35 N - 25 N=10 N.

- Object Y:  the resultant on the vertical direction is zero, because we have two opposite forces with same magnitude (60 N), so they cancel each other. Also, the resultant on the horizontal direction is zero, because we do not have forces along this direction.

- Object Z: the resultant on the vertical direction is zero, because we have two opposite forces with same magnitude (45 N), so they cancel each other. However, the resultant on the horizontal direction is NOT zero, because the net force is 22 N, not balanced from the other direction.

Therefore, objects W and Y have balanced forces, and objects X and Z have unbalanced forces.

5 0
3 years ago
Read 2 more answers
In a fluorescent tube of diameter 4.8 cm , 2.7 × 1018 electrons (with a charge of −e) and 2.4 × 1018 positive ions (with a charg
Lesechka [4]

Answer: 0.817A

Explanation:

Assuming , that one coulomb per second of negative charge alone flow through a conductor and no positive charges flow. I.e Q=It

It means a current of one A flow in the opposite direction.

This is similar to one coulomb per second of positive charge flowing through and there is no negative charge,

In addition, the one coulomb per second of positive charge flows. This is flowing in the current direction of the previous one. Then, the total current is 2 A. Since 2 coulomb of positive charges flow through one due to real positive charge and another due to the negative charge flowing in opposite direction.The charges cannot cancel each other, because even before the current flow the conductor was neutral.

According to this, the current in the given problem is

[2.7 + 2.4] x 10 ^ 18 * 1.602 x 10^ [-19] C/s

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7 0
3 years ago
A Brayton cycle has air into the compressor at 95 kPa, 290 K, and has an efficiency of 50%. The exhaust temperature is 675 K. Fi
motikmotik

Answer:

The specific heat addition is 773.1 kJ/kg

Explanation:

from table A.5 we get the properties of air:

k=specific heat ratio=1.4

cp=specific heat at constant pressure=1.004 kJ/kg*K

We calculate the pressure range of the Brayton cycle, as follows

n=1-(1/(P2/P1)^(k-1)/k))

where n=thermal efficiency=0.5. Clearing P2/P1 and replacing values:

P2/P1=(1/0.5)^(1.4/0.4)=11.31

the temperature of the air at state 2 is equal to:

P2/P1=(T2/T1)^(k/k-1)

where T1 is the temperature of the air enters the compressor. Clearing T2

11.31=(T2/290)^(1.4/(1.4-1))

T2=580K

The temperature of the air at state 3 is equal to:

P2/P1=(T3/T4)^(k/(k-1))

11.31=(T3/675)^(1.4/(1.4-1))

T3=1350K

The specific heat addition is equal to:

q=Cp*(T3-T2)=1.004*(1350-580)=773.1 kJ/kg

3 0
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