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2 years ago

What is the slop of the line A. 2 B. -1/2 c.1/2 D.- 2 Somebody pls help me

Mathematics

2 answers:

cupoosta [38]2 years ago

8 0

Answer:

its 1/5

Step-by-step explanation:

neonofarm [45]2 years ago

7 0

Answer:

1/5

Step-by-step explanation:

trust me its the answer or

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The UK has an area of 243,610km2 and a population of 6.41 x 107. Calculate the population density the United Kingdom. Answer to

hodyreva [135]

Answer: Population density the United Kingdom $=2.63\times10^2$

A= 2.63

B= 2

Step-by-step explanation:

We know that, to calculate the population density, we will divide the population by the size of the area.

i.e. $\text{Population density}=\dfrac{\text{Population size}}{\text{Area}}$

Given : Area of UK = 243,610 km²1

Population = $6.41 \times 10^7$

Then, the population density the United Kingdom would be :

$\text{Population density}=\dfrac{6.41 \times 10^7}{243,610}\\\\=\dfrac{64100000}{243610}=263.125487459\\\\\approx263=2.63\times10^2$

On comparing to $A\times10^B$ , we get

A= 2.63

B= 2

3 0

3 years ago

Ming argues that the length of a will be half of the measure of the length of 6 since 45° is half the measure of 90°. Charlene a

Afina-wow [57]

The length of a will be a different number and the value will be 4.71in

<h3>How to find the area of a sector</h3>

The given diagram is a sector and the formula for calculating the length of an arc is expressed as:

Length of an arc = rβ

where

β is the subtended angle
r is the radius

Given the following parameters

β .= 45 degrees

r = 6in

Substitute

Length of an arc = 6π/4

Length of an arc = 6(3.14)/4

Length of an arc = 4.71inches

This shows that the length of a will be a different number and the value will be 4.71in

Learn more on length of arc here: brainly.com/question/8020286

#SPJ1

5 0

2 years ago

Yo how is the answer

seraphim [82]

Answer:

I think it's 18 but I'm not sure

6 0

2 years ago

SOLVE THIS <br>VERY IMPORTANT QUESTION

tester [92]

Answer:

Step-by-step explanation:

$\dfrac{Cos \ A}{1 + Sin \ A}=\dfrac{Cos \ A *(1-Sin \ A)}{(1+Sin \ A)(1 - Sin \ A)}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{1^{2}-Sin^{2} \ A}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{Cos^{2} \ A}\\\\\\=\dfrac{1-Sin \ A}{Cos \ A}$ ------(I)

$LHS =\dfrac{Cos \ A}{1+Sin \ A}+\dfrac{1+Sin \ A}{Cos \ A}\\\\\\ = \dfrac{1-Sin \A}{Cos \ A}+\dfrac{1+Sin \ A}{Cos \ A} \ [from \ equation \ (I)]\\\\\\=\dfrac{1-Sin \ A + 1 - Sin \ A}{Cos \ A}\\\\=\dfrac{2}{Cos \ A}\\\\\\=2*Sec \ A = RHS$

3 0

2 years ago

Evaluate the following expression for y=25 and g=5<br><br>8(y÷g)-4y÷g+9<br><br>

Lorico [155]

Answer:

Step-by-step explanation:

7 0

2 years ago

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