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Virty [35]
2 years ago
7

SOLVE THIS VERY IMPORTANT QUESTION​

Mathematics
1 answer:
tester [92]2 years ago
3 0

Answer:

Step-by-step explanation:

\dfrac{Cos \ A}{1 + Sin \ A}=\dfrac{Cos \ A *(1-Sin \ A)}{(1+Sin \ A)(1 - Sin \ A)}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{1^{2}-Sin^{2} \ A}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{Cos^{2} \ A}\\\\\\=\dfrac{1-Sin \ A}{Cos \ A}------(I)

LHS =\dfrac{Cos \ A}{1+Sin \ A}+\dfrac{1+Sin \ A}{Cos \ A}\\\\\\ = \dfrac{1-Sin \A}{Cos \ A}+\dfrac{1+Sin \ A}{Cos \ A} \ [from \ equation \ (I)]\\\\\\=\dfrac{1-Sin \ A + 1 - Sin \ A}{Cos \ A}\\\\=\dfrac{2}{Cos \ A}\\\\\\=2*Sec \ A = RHS

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Determine the missing side length:
ludmilkaskok [199]
The answer is:  "3" .
_______________________________
Use the Pythagorean theorem (for right triangles):

a² + b² = c² ;

in which "a = "side length 1" (unknown; for which we which to solve);

               "b" = "side length 2" = "√3" (given in the figure) ;

               "c" = "length of hypotenuse" = "2√3" (given in the figure);
_____________________________________________________
a² + b² = c² ; 

a² = c² − b² ;

Plug in the known values for "c" and "b" ;

a² = (2√3)²  −  (√3)² ;

Simplify:

(2√3)² = 2² * (√3)² = 2 * 2 * (√3√3)  = 4 * 3 =  12 .

 (√3)²  = (√3√3) = 3 .

a²  = 12 − 3 = 9 .

a² = 9

Take the "positive square root" of EACH SIDE of the equation; to isolate "a" on one side of the equation;  & to solve for "a" ; 

+√(a²)  = +√9 ;

     a = 3 . 
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The answer is:  "3" .
____________________________________
3 0
3 years ago
What dimensions of the box are required to fit the candle? 5 by 6 by 18 7 by 6 by 18 5 by 3 by 18 7 by 3 by 18
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We have not been given the other dimension of the triangle, but from common sense, it looks longer than the front (5 units) leg, therefore 6 units is not an unreasonable dimension.

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The Correct Answer Is B.36 square centimeters
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8_murik_8 [283]
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