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Readme [11.4K]
3 years ago
6

what is the equation of the line that is perpendicular to line m and passes through the point (3, 2)?

Mathematics
1 answer:
iragen [17]3 years ago
6 0

Answer:

y = 2/5x + 4/5

or

y = 2/5x +0.8, both mean the same thing

Step-by-step explanation:

Perpendicular line would mean that the line has to go through line m at a 90 degree angle.

The first thing I would do is look at the slope already given to us for line m and flip it around and make the negative fraction a positive one so it goes up.

-5/2x -> 2/5x

The next would be to find where the line would intercept on the y-axis. It already told us it will go through the point (3,2). So with the slope we already have, count 5 to the left and 2 down. At this point I plotted this entire thing in a graphing calculator. Anyways the answer:

y = 2/5x + 4/5

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Two opposite numbers are 18 units away from each other. What are the numbers?
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Step-by-step explanation:

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2 years ago
The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i
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Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

S=\pi r\sqrt{r^2+h^2}

and volume,

V=\frac{1}{3}\pi r^2 h

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

f(r,h)=\frac{1}{3}\pi r^2 h

subject to,

g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)

We know for maximum volume r\neq 0. So let \lambda be the Lagranges multipliers be such that,

f_r=\lambda g_r

\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)

And,

f_h=\lambda g_h

\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}

\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)

Substitute (3) in (2) we get,

\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)

\implies h^2=2r^2

Substitute this value in (1) we get,

\pi r\sqrt{h^2+r^2}=8

\implies \pi r \sqrt{2r^2+r^2}=8

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Then,

h=\sqrt{2}(1.21252)\equiv 1.71476

Hence largest volume,

V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114

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