Answer:
pH = 12.80
[H3O+] = 1.58 * 10^-13 M
[OH-] = 0.063 M
Explanation:
Step 1: Data given
pOH = 1.20
Temperature = 25.0 °C
Step 2: Calulate pH
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 1.20 = 12.80
Step 3: Calculate hydronium ion concentration
pH = -log[H+] = -log[H3O+]
12.80 = -log[H3O+]
10^-12.80 = [H3O+] = 1.58 * 10^-13 M
Step 4: Calculate the hydroxide ion concentration
pOH = 1.20 = -log [OH-]
10^-1.20 = [OH-] = 0.063M
Step 5: Control [H3O+] and [OH-]
[H3O+]*[OH-] = 1* 10^-14
1.58 *10^-13 * 0.063 = 1* 10^-14
The cells that result from the reproductive division of one cell during mitosis or meiosis
Preparation of small volumes of gases.
The area of the base is
Ab = 2.1 cm x 5.6 cm
The least number of significant figures is 2, so the number of significant figures of the product must also be 2.
Ab = 11.76 cm² which must be rounded-off to 12 cm²<span />
The answer is A
Hope this helps