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Sergeu [11.5K]
3 years ago
14

What is a metal oxide and hiw are they formed?

Chemistry
1 answer:
mamaluj [8]3 years ago
7 0

It is a <u><em>chemical compound</em></u> formed with a metal (mainly positive cations) with oxygen.

It is formed through the air as they react in the air together.

They are also BASES - ALKALINE (so neutralise acids)

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Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop
Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

                     Mg  +   Cu(NO₃)₂    ⇒    Mg(NO₃)₂   +   Cu

                  Reactants           Elements            Products

                         1                          Mg                     1

                         1                          Cu                      1

                         2                          N                       2

                         6                          O                       6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

                                              = 24 + 28 + 96

                                              = 148 g

                           24 g of Mg  --------------------  148 g of Mg(NO₃)₂

                          147.4 g of Mg -------------------   x

                            x = (147.4 x 148) / 24

                            x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = \frac{actual yield}{theoretical yield}

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = \frac{30.8}{100} x 908.96

Actual yield = 279.95 ≈ 280g

                     

4 0
3 years ago
SiO2 + 4HF = SiF4 + 2H2O, what mass of HF is necessary to produce 12.91g of the SiF4?
ahrayia [7]
i dont know broooooooooooooooooooooooooooooooooooooooooooioooooooooooooooooooooooooooooooooo i wish i knew
7 0
3 years ago
When you stand in flowing water, you can feel the water pulling you with it. Imagine that the water was replaced with a more vis
IceJOKER [234]

Answer:

If one is standing in flowing water and thicker liquid, it will be easier to resist the force of the thicker liquid in comparison to water .

It is so because the thicker liquid has an internal resistance that acts when the liquid is in motion, and it is easy to oppose the motion of thicker liquid while water do not have internal resistance and it become harder to resist teh force.

5 0
3 years ago
Read 2 more answers
If you have 2 moles of an element, how many particles do you have?
Amanda [17]

Answer:

1.204×10^24 particles of element

Explanation:

1mol=6.02×10^23 number of particles (in this case an element)

2mol=(6.02×10^23)×2 particles of the element

=1.204×10^24 particles of element

*be careful aware significant digits

3 0
3 years ago
If 55.0 mL of ethanol (density=0.789g/mL)) initially at 9.0 ∘C is mixed with 55.0 mL of water (density=1.0g/mL) initially at 28.
juin [17]

Answer:

Final temperature = 22.21  °C

Explanation:

Heat gain by ethanol = Heat lost by water

Thus,  

m_{ethanol}\times C_{ethanol}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{ethanol}\times C_{ethanol}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)

<u>For ethanol: </u>

Density = 0.789 g/mL

Volume = 55.0 mL

Considering the expression for density as:

Density=\frac {Mass}{Volume}

So,

So, Mass= Density*Volume = 0.789 g/mL * 55.0 mL = 43.395 g

Initial temperature = 9.0 °C

Specific heat of ethanol = 2.57 J/g°C

<u>For water: </u>

Density = 1.0 g/mL

Volume = 55.0 mL

Considering the expression for density as:

Density=\frac {Mass}{Volume}

So,

So, Mass= Density*Volume = 1.0 g/mL * 55.0 mL = 55.0 g

Initial temperature = 28.6 °C

Specific heat of water = 0.450 J/g°C

So,  

43.395\times 2.57\times (T_f-9.0)=55.0\times 4.186\times (28.6-T_f)

111.52515\times T_f-1003.72635=6584.578-230.23\times T_f

341.75515\times T_f=7588.30435

<u>Final temperature = 22.21  °C  </u>

6 0
3 years ago
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