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Sergeu [11.5K]
3 years ago
14

What is a metal oxide and hiw are they formed?

Chemistry
1 answer:
mamaluj [8]3 years ago
7 0

It is a <u><em>chemical compound</em></u> formed with a metal (mainly positive cations) with oxygen.

It is formed through the air as they react in the air together.

They are also BASES - ALKALINE (so neutralise acids)

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Metamorphism can best be defined as
Brilliant_brown [7]

Answer:

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What is the mass of a neutron?<br><br> 1/2,000 amu<br> 1 amu<br> 2,000 amu<br> 1/200 amu
pashok25 [27]

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-Zayn Malik
8 0
3 years ago
Read 2 more answers
A compound is composed of C, H and O. A 1.621 g sample of this compound was combusted, producing 1.902 g of water and 3.095 g of
vlada-n [284]

Answer: The molecular of the compound is, C_2H_3O

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=3.095g

Mass of H_2O=1.902g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.095g of carbon dioxide, \frac{12}{44}\times 3.095=0.844g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.902g of water, \frac{2}{18}\times 1.092=0.121g of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (1.621)-[(0.844)+(0.121)]=0.656g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.844g}{12g/mole}=0.0703moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.121g}{1g/mole}=0.121moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.656g}{16g/mole}=0.041moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.041 moles.

For Carbon = \frac{0.0703}{0.041}=1.71\approx 2

For Hydrogen  = \frac{0.121}{0.041}=2.95\approx 3

For Oxygen  = \frac{0.041}{0.041}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 2 : 3 : 1

Hence, the empirical formula for the given compound is C_2H_3O_1=C_2H_3O

The empirical formula weight = 2(12) + 3(1) + 1(16) = 43 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{46.06}{43}=1

Molecular formula = (C_2H_3O_1)_n=(C_2H_3O_1)_1=C_2H_3O

Therefore, the molecular of the compound is, C_2H_3O

6 0
3 years ago
What compound is this?
Nezavi [6.7K]

Answer:

Carbon Tetrachloride

Explanation:

1 Carbon atom, 4 chlorine atoms (hence "tetra" prefix)

7 0
3 years ago
Chlorine is a halogen and has 7 valence electrons, which is represented by crosses on the left
makkiz [27]

There are 2 electrons in the overlapping region.

Chlorine is the second member of the halogen group which are form of family of elements that resemble one another very closely.

The electronic configuration of chlorine shows the arrangement of chlorine electrons within it's atom.

At the outer most shell of the atom is seven electrons, therefore requires only one electron each to attain the octet arrangement.

The overlapping of the orbitals indicates the chemical bond formed by sharing of electrons between atoms called covalent bonding.

To complete it's outer most shell, it will need to share electron with another chlorine atom.

Therefore, there are 2 electrons in the overlapping region.

Learn more here:

brainly.com/question/16396974

3 0
3 years ago
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