The initial velocity is equal zero
and the cat falls freely so the acceleration equal 9.81 m/s^2
V = Vo + g * t
V = 0 + (9.81 * 2.6)
V = 25.5 m/s
Answer:
38.0 g C2F3Cl3) / (187.3756 g C2F3Cl3/mol) x (3 mol Cl / 1 mol C2F3Cl3) x (35.4532 g Cl/mol) =
21.6 g Cl in C2F3Cl3
The answer is (3), oxidation occurs at the anode and reduction occurs at the cathode. That's because the oxidation reaction can lose electrons and reduction can gain electrons.
