<span>Let’s assume the number of problems as P
Student did his homework = (3/5) P + 8
Father did the homework = (1/5) P + 7
So the sum of the both equations is equal to P
=> (3/5) P + 8 + (1/5) P + 7 = P
=> (4/5) P + 15 = P
=> 4P + 75 = 5P
=> P = 75
Problems they solve together are 75 problems.</span>
<span>y=2x+3 (Total vacation time equals 2 days times x plus the 3 days he was given at the start.
Each year has 2 six-month periods. After 4.4 years Roberto will have worked 8.8 six-month periods. He will have been given vacation days for each of the 8 whole working periods he has completed.
x=8
y=2*8+3
y=19</span>
Answer:
B. 1/m¹⁸
Step-by-step explanation:
To simplify the equation, we start with the values inside the brackets.
Therefore m⁻¹m⁵ results to m⁴.
This is because the sign between the m⁻¹ and m⁵ is multiplication, and when multiplying figures that have a similar base, we add the indices.
that is, -1+5=4
then we divide m⁴ by m⁻², that is, m⁴/m⁻²=m⁶
To divide figures that have the same base we subtract the powers.
That is, 4-(-2)=6
the resulting expression from inside the brackets will be (m⁶)³ which results to m⁻¹⁸ which is the same as 1/m¹⁸
Answer:
Part A: 1.25g + 14.25 <u><</u> 55.00
Part B: 32 games
Step-by-step explanation:
A:
price per game * games played (1.25g) + money he's already spent (14.25)
must be less than or equal to his total budget (55.00)
equation: 1.25g + 14.25 <u><</u> 55.00
B:
total (55.00) - already spent (14.25) = what he can spend on games (40.75)
55.00 - 14.25 = 40.75
arcade budget (40.75) / cost per game (1.25) = 32.6
because you can't play 0.6 games, 32 games
