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pogonyaev
2 years ago
7

100 PTS:Please help me now plz plz

Mathematics
2 answers:
Alex Ar [27]2 years ago
4 0

Answer:

x = 12

Step-by-step explanation:

We have a right triangle with hypotenuse 10 and the height 8.  Either the one on the left or the one on the right

We can find the base using the Pythagorean theorem

a^2 + b^2 = c^2

a^2 +8^2 = 10^2

a^2  +64 = 100

Subtract 64 from each side

a^2 = 100 -64

a^2 = 36

Take the square root of each side

a = 6

Now a is 1/2 of the total base of the big triangle.  It is identical since the triangles are equal

x = 2 * a

x = 2*6 = 12

nataly862011 [7]2 years ago
4 0

Answer:

x = 12

Step-by-step explanation:

Consider the right angle triangle with

base: x/2

height: 8

hypotenuse: 10

Using pythagoras theorem

10² = 8² + (x/2)²

(x/2)² = 100 - 64

(x/2)² = 36

x/2 = 6

x = 12

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The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.

Step-by-step explanation:

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\mu_{x} \pm M

In which \mu_{x} is the mean of the sample and M is the margin of error.

In this problem, we have that:

\mu_{x} = 28, M = 2.2

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The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.

4 0
3 years ago
The edge of a cube was found to be 30 cm with a possible error in measurement of 0.5 cm. Use differentials to estimate the maxim
IgorLugansk [536]

Answer:

for the volume a cube

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Percentage error = 5%

For the surface area of a cube

Possible error = 180cm²

Relative error = 0.0333

Percentage error = 3.33%

Step-by-step explanation:

A cube is a three dimensional solid object with six (6) faces, twelve (12) edges and eight(8) vertices.

The volume of a cube = x³

Where x= length of the edge of a cube

X = 30cm 0.5cm

Differentiate V with respect to x (V = Volume of a cube)

dV/dx= 3 x²

dV= 3 x² . dx

dV = 3 × 30² × (0.5)

dV= 2700(0.5)

= 1350cm³

Maximum possible error = 1350cm³

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= dV/V

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A = 27000cm³

Substitute the values for and V into the formula for Relative error

Relative error = 1350/27000

Relative error = 0.05

% error = Relative error × 100

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Surface Area of a cube = 6x²

A = 6x²

Differentiate A with respect to x

dA/dx = 12x

dA/dx = 12x . dx

= 12 × 30 (0.5)

= 180cm²

Maximum possible error = 180cm²

Relative error = possible error / surface area

= dA/A

Recall that A = 6x²

A = 6(30)²

A = 5400cm²

Substitute the values for and A into the formula for Relative error

Relative error = 180/5400

Relative error = 0.0333(4 decimal place)

% error = Relative error × 100

= 0.0333 × 100

= 3.33%

8 0
3 years ago
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