Log_(10)(x² - 4x + 7) = 2
Take the base 10 anti log of both sides.
x² - 4x + 7 = 10² = 100
x²- 4x - 93 = 0
Quadratic Formula
x = [4 ± √(4²-4(1)(-93))]/[2(1)] = [4 ± 2√97)]/2 = 2 ± √97
Answer:
10c = 20
5c = 5
Step-by-step explanation:
Let x be the number of 10c coins; let y be the number of 5c coins. The total is $2.25, so the amount of 10c and 5c coins will add to that. Simita has 25 coins, so x and y, the number of coins, will have to add to 25. Hence, solve the simultaneous equation.
10x + 5y = 225 (1) - times by 0
x + y = 25 (2) - times by 5
10x + 5y = 225 (1)
5x + 5y = 125 (2)
Then, take equation 2 away from equation 1.
5x = 100
x = 20
Substitute x back into the original equation.
x + y = 25
20 + y = 25
y = 5
Answer:
Cost of each daylilies = $3
Cost of each ivy pot = $3
Step-by-step explanation:
Given:
Cost of 4 daylilies and 4 ivy = $24
Cost of 4 daylilies and 8 ivy = $36
Find:
Cost of each daylilies
Cost of each ivy pot
Computation:
Assume;
Cost of each daylilies = a
Cost of each ivy pot = b
So,
4a + 4b = 24....... eq 1
4a + 8b = 36 ....... eq 2
Eq2 - Eq1
8b - 4b = 36 - 24
4b = 12
b = 3
So,
Cost of each ivy pot = $3
4a + 4b = 24
4a + 4(3) = 24
4a + 12
a = 3
Cost of each daylilies = $3
Y = mx + b
m = -2, b = 4
<span>y = -2x + 4</span>
