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pishuonlain [190]

2 years ago

8

Angie baked 100 cookies and Tony brownies she wants to split them into equal groups for the bake sale each group must have the s

ame number of cookies and brownies with no leftover what is the greatest number of groups she can make?

1 answer:

Korvikt [17]2 years ago

8 0

She can make 50 group

100^2=50
So she will put 2 cookies in every group

And she can make 100 group if she put one cooky in every group

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Hector spent $41.75 for 2 DVDs that cost the same amount. The sales tax on his purchase was $3.15. Hector also used a coupon for

kykrilka [37]

Given:

Amount spent on 2 DVDs = $41.75

Sales tax = $3.15

Coupon = $1.00 off

To find:

The cost of each DVD.

Solution:

Let x be the cost of each DVD.

Then, cost of two DVDs = 2x

Amount spent of 2 DVDs = Cost of 2 DVDs + Sales tax - Coupon discount

$41.75=2x+3.15-1.00$

$41.75=2x+2.15$

$41.75-2.15=2x$

$39.6=2x$

Divide both sides by 2.

$\dfrac{39.6}{2}=x$

$19.8=x$

Therefore, the cost of each DVD is $19.8.

8 0

2 years ago

Solve for x: log2(8)=x

Kitty [74]

X=16log i’m guessing not sure:)

4 0

3 years ago

Attachment mathswatch!!!!!!!!!!!!!

SSSSS [86.1K]

Answer:

a) = Slope of line AB = 1/2

<h2><em><u>Perpendicular = -2</u></em></h2>

<h2>b) <em><u>y = -2x + 6</u></em></h2><h2 />

Step-by-step explanation:

a) When it is perpendicular the answer will be positive if the initial value is negative. If it is a whole number, then the perpendicular number is going to be a fraction. The opposite applies.

b) Slope = -2x

intercept = ?

y = -2x + b

0 = -6 + b

+6 +6

b = 6

<em><u>y = -2x + 6</u></em>

7 0

2 years ago

Read 2 more answers

stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n

Anon25 [30]

Given functions are

$s(n)=2(1.1)^n+5_{}$ $d(n)=4(1.08)^n+3$

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

$t(n)=s(n)+d(n)$

$t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)$

$t(n)=2(1.1)^n+5+4(1.08)^n+3$

$t(n)=2(1.1)^n+4(1.08)^n+5+3$

$t(n)=2(1.1)^n+4(1.08)^n+8$

Taking 2 as common, we get

$t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack$

Hence The total number of ducks and swans in the lake after n months is

$t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack$

8 0

1 year ago

Every orthogonal matrix is diagonalizable. O True O False

Simora [160]

Answer:

FALSE

Step-by-step explanation:

the correct answer is FALSE

A matrix is said to be orthogonal when it is multiplied by its own transpose then the matrix comes out to be Identity.

$A^T.A = I$

the basic condition for a matrix to be diagonalizable is that the matrix should be symmetric.

but an orthogonal matrix is not necessarily symmetric so, the statement is false.

5 0

2 years ago