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babymother [125]
2 years ago
8

Help me awnser these questions please

Mathematics
1 answer:
Naya [18.7K]2 years ago
8 0

Answer: y=x-1

General equation of linear function: y=mx+b

A(-1;0); x=-1, y=0

B(0;-1); x=0, y=-1

Let's solve the system of equations

\displaystyle\\\left \{ {{0=-1m+b} \atop {-1=0x+b}} \right. =>b=-1=>0=-m-1;m=-1

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Solve the following quadratic equation:
Advocard [28]

Answer:

-3.5 or -6

Step-by-step explanation:

2x^2+19x+40=-2

2x^2+19x+40+2=0

2x^2+19x+42=0

2x^2+(12+7)x+42=0

2x^2+12x+7x+42=0

2x(x+6)+7(x+6)=0

(x+6)(2x+7)=0

either,

x+6=0

x=-6

or,

2x+7=0

2x=-7

x=-7/2

x=-3.5

4 0
3 years ago
Decide whether the triangles are similar. If so, determine the appropriate expression to solve for
astraxan [27]

Answer:

ΔABC ~ ΔEDF; x = r × w/z

Step-by-step explanation:

m∠ABC = 180 -47 - 62 =71 = m∠EDF

ΔABC ~ ΔEDF

w/z = x/r

x = r × w/z

6 0
3 years ago
Read 2 more answers
Diego is 59.5 inches tall. His brother is 40.125 inches tall. How much taller than his his brother is Diego?
lukranit [14]
He is 1 inch. Taller
6 0
2 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
Read 2 more answers
Is it scalene isosceles or equilateral then write acute obtuse or right thx
almond37 [142]
It's scalene because it has different sides and obtuse because root 40²+30²=50
110>50
4 0
3 years ago
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