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AlexFokin [52]
3 years ago
12

5% of 40 pounds working out calculating the given percentage of a number​

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Answer:

5% of 40 is 2, 50% of fourth is twenty and so on.

Step-by-step explanation:

To get my ander which ios two i multiplied 5% x 40, the answer is 2.

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A gift shop sells 140 wind chimes per month at $90 each. The owners estimate that for each $5 increase in price, they will sell
guapka [62]

Answer: $95

Step-by-step explanation:

Te new price will be 90 + 5x, if the price increases "x" times

The number of wind chimes sold per month will become 140 - 7x

\begin{aligned}&\text {Revenue, } \mathrm{R}(\mathrm{x})=(90+5 \mathrm{x})(140-7 \mathrm{x}) \\&R^{\prime}(x)=5(140-7 x)-7(90+5 x) \\&R^{\prime}(x)=700-35 x-630-35 x \\&R^{\prime}(x)=70-70 x=0 \\&70 x=70 \\&x=1\end{aligned}

Therefore, if the price becomes (90 + 5(1)) = $95 per wind chime, then the revenue will be maximum

6 0
3 years ago
One day, the Early Bird Restaurant used
stiks02 [169]

Answer:

F. 23

Step-by-step explanation:

15/2 = 7.5

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15 + 7.5 = 22.5 which can be rounded to 23

= 23

3 0
2 years ago
Using the image, find the slope of the line. Reduce all fractions and enter using a forward slash (i.e. "/"). If the slope is un
dusya [7]

9514 1404 393

Answer:

  0

Step-by-step explanation:

The slope of a horizontal line is zero (0). For any finite "run", the "rise" is zero.

  slope = rise/run = 0/run = 0

8 0
3 years ago
Line FG contains points F(3,7) and G (-4,-5)
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What are you supposed to be finding? Give More Information Plz. <span />
3 0
4 years ago
The equation of line r is y = -1\2x - 4. If line s runs perpendicular to line r and passes through (4, -3), what would be the eq
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First off, what's the slope of "r" anyway,   \bf y=\stackrel{slope}{-\cfrac{1}{2}}x-4.

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now, any line perpendicular to "r", will have a negative reciprocal slope to it, that is,

\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -\cfrac{1}{2}\\\\&#10;negative\implies  +\cfrac{1}{{{ 2}}}\qquad reciprocal\implies + \cfrac{{{ 2}}}{1}\implies 2

so we're really looking for a line whose slope is 2, and runs through 4,-3,

\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1\\&#10;%  (a,b)&#10;&&(~{{ 4}} &,&{{ -3}}~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}\implies 2&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-3)=2(x-4)\implies y+3=2x-8&#10;\\\\\\&#10;y=2x-11
7 0
4 years ago
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