Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
$78.72
Step-by-step explanation:
To find 30% of the original value, we need to turn this percentage into a decimal or a fraction and then multiply it by the original value
- 30% is equivalent to 0.30,
, and 
- So we can use either of these values. I will use 0.30 for simplicity
- ($262.40)(0.30) = $78.72 is the amount saved
Answer:
hmmmm lemme think. id say simplify the top and bottom then divide. im kinda busy rn so i cant do it. sorry bro but what grade is this and i could help you some more in the future ok :)
Step-by-step explanation:
Polynomial A : x^4 + 2 x³ - x² + 7 x + 11 has a Quartic degree.
Polynomial B : x² + 4 x is a Quadratic binomial.
Polynomial D : 5 x² - 2 x + 4 has a Quadratic degree.
Answer:
Polynomial D : 3 x^5 + 2 is a Quintic binomial
