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kolbaska11 [484]
2 years ago
11

If 5 for 25.59 how much for 9

Mathematics
1 answer:
Kamila [148]2 years ago
3 0

Answer: 9 for $46.06

Step-by-step explanation:

25.59/5=5.118

That means 1 for 5.118

5.118x9=46.062

That means 9 for 46.062

This is money, so round 46.062 to be $46.06

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Keith bought 6 new baseball trading cards to add to his collection. The next
sergeinik [125]

Keith started with 44 cards.

So we need to work backwards.

After his dog ate half his collection, he had 25 cards.

To reverse that, you need to multiply 25 by 2.

25×2=50

If he bought 6 new cards that day, then he started with 6 cards less.

So you have to subtract 6 from 50.

50-6=44

♡ Hope this helped! ♡

❀ 0ranges ❀

4 0
3 years ago
Find m<1 and m<2 help please, ASAP, explain:(
olga_2 [115]

Answer:

m<1 = 108

m<2 = 72

Step-by-step explanation:

3 0
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Polynomial<br> 27 – 3x3 - 2x<br> Standard form
NISA [10]

Answer:

-3x^3-2x+27 \ is\ the\ standard\ form.

Step-by-step explanation:

The standard form of a polynomial is its representation in a descending order starting from the term with the highest degree to the one with the lowest.

Here,-3x^3-2x+27 \ is\ the\ standard\ form.

3 0
3 years ago
NOTE: Angles not necessarily drawn to scale.
JulsSmile [24]

Answer:

x=70

Step-by-step explanation:

angle FED and GEC are vertical angles so they both equal 50

angle DEB and CEA are also vertical angles so they both equal 20

50+20=70

8 0
3 years ago
The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E
Gnoma [55]

Answer:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

Step-by-step explanation:

Given

\triangle ABC {\displaystyle \sim } \triangle DE\ F

AC = 10

AB = 5

\angle C = 30^\circ

ED = 7.5

DF = 25

\angle F =30

\angle E =90

Required

Which of the options is/are true:

\triangle CBA {\displaystyle \sim } \triangle FED            \triangle CBA {\displaystyle \sim } \triangle FDE              \triangle BAC {\displaystyle \sim } \triangle EFD

\triangle BAC {\displaystyle \sim } \triangle EDF            \triangle ABC {\displaystyle \sim } \triangle DE\ F             \triangle ABC {\displaystyle \sim } \triangle DFE

The given triangles, implies that:

A {\displaystyle \sim } \ D

B {\displaystyle \sim } \ E

C {\displaystyle \sim } \ F

By taking each sides of both triangle, one after the other; the possible similar triangles are:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

5 0
3 years ago
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