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2 years ago

Proofs please help I don’t get this and need it very soon

Mathematics

1 answer:

Flauer [41]2 years ago

7 0

I think its the same thing but what are the options? (Reply)

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Why is division not commutative

Kamila [148]

Division CANNOT be commutative, here is why

lets say the problem is 24÷4

it is obviously 6

but when you flip 24÷4, you get 4÷24

and... 4÷24 is 0.16666666

6 and 0.1666 is totally different :p

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3 years ago

11. It took Mr. Owen 12 hours to build

Charra [1.4K]

Answer:

3 feet per hours

Step-by-step explanation:

To get unit rate divide foot by hours

$\frac{36}{12} = 3$

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3 years ago

Read 2 more answers

Ten increased by 6 times a number is the same as 4 less than 4 times the number

Gelneren [198K]

Express into algebraic form
10 + 6x = 4x - 4

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3 years ago

Convert 13 feet per second to feet per hour

Svet_ta [14]

Answer:

0.681818

Step-by-step explanation:

13 feet per second is equal to 0.681818 miles per hour.

3 0

3 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago