1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tino4ka555 [31]
2 years ago
12

Find the LCM of the each set of numbers 7,14

Mathematics
2 answers:
kipiarov [429]2 years ago
5 0

List common multiples of 7: 7,14,21,28,35,42 ...

List common multiples of 14: 14,28,...

So, the Least common multiple is 14

il63 [147K]2 years ago
5 0

the LCM of 7 and 14 is 14.

•7= 0, 7, 14, 21, 28, ...

•14= 0, 14, 28, 42, ...

since we are looking for the least common multiple, then it is 14.

You might be interested in
Please help ASAP!! Will give brainliest to correct answer!
snow_lady [41]

Answer:

2/4

Step-by-step explanation:

4 0
3 years ago
Given EG = 16 and FH = 12, what is the length of one side of the rhombus? 6 units 8 units 10 units 14 units PLEASE HELP ONLY COM
ZanzabumX [31]
EG and FH are diagonals of the rhombus and the bisect each other at the centre to for a righ angle triangle with the side of the rhombus as the hypothenus.
By pythagoras theorem, length = \sqrt{ 8^{2} + 6^{2} } = \sqrt{64+36} = \sqrt{100} =10 \ units
5 0
3 years ago
Read 2 more answers
NEED HELP!<br> Problem is in the photo.
devlian [24]

b 2x-y=-4. is the answer

3 0
3 years ago
Read 2 more answers
!!30 POINTS!!<br> Name the ray that is opposite RS
Rama09 [41]

Answer:

RP is the correct amswer.

Step-by-step explanation:

please mark me as a brainlist...

8 0
2 years ago
(b) If a series follows geometric progression, show that the ratio of the sum of term to the sum from (n+1) term to (2n) term is
Nadusha1986 [10]

Proof with explanation:

We know that the sum of first 'n' terms of a Geometric progression is given by

S_{n}=\frac{a(1-r^{n})}{1-r}

where

a = first term of G.P

r is the common ratio

'n' is the number of terms

 Thus the sum of 'n' terms is

S_{n}=\frac{a(1-r^{n})}{1-r}

Now the sum of first '2n' terms is

S_{2n}=\frac{a(1-r^{2n})}{1-r}

Now the sum of terms from (n+1)^{th} to (2n)^{th} term is S_{2n}-S_{n}

Thus the ratio becomes

\frac{S_{n}}{S_{2n}-S_{n}}\\\\=\frac{\frac{a(1-r^{n})}{1-r}}{\frac{a(1-r^{2n})}{1-r}-\frac{a(1-r^{n})}{1-r}}\\\\=\frac{1-r^{n}}{r^{n}-r^{2n}}\\\\=\frac{1-r^{n}}{r^{n}(1-r^{n})}\\\\=\frac{1}{r^{n}}

5 0
2 years ago
Other questions:
  • How to solve an expression with variables in the exponents?
    5·1 answer
  • Simplify (3x − 5) − (4x + 6).
    15·1 answer
  • How many solutions does the following system of equations have?
    11·2 answers
  • b. What would be the new account balance in five years at a 5.12% if the interest was compounded monthly?
    11·1 answer
  • How to solve 4|x+6|greater than or equal to 20
    6·1 answer
  • A number is 42,300 when multiplied by 10. Find the product of this number and 500.
    7·1 answer
  • Express the hcf/lcm of 48 and 18 as a linear combination
    8·1 answer
  • X= 4y +7<br> 2x - 6y= 12
    7·2 answers
  • PLS HELP ILL MARK U BRAINLIEST<br> I DID THE FIRST 1 I NEED HELP WITH THE SECOND &lt;3
    6·1 answer
  • When multiplying two negative numbers, what kind of number does one always get for an answer?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!