Since BD bisects angle ABC, that means angle ABD and angle CBD are equal to each other. With that set up the equation to solve for x like this:
-4x+33 = 2x+81
-2x -2x
————————
-6x +33 = 81
-33 -33
————————
-6x = 48
————- (divide by -6)
-6
x = -8
Now substitute that to ABD
-4(-8) +33
32 +33
=65
here’s CBD
2(-8) + 81
-16 + 81
=65
Finally angle ABC will be double the amount of ABD or CBD so 65 times 2 is 130.
ANSWERS: (angles)
ABD and CBD: 65
ABC: 130
1.) f(x)=7(b)^x-2
x=0→f(0)=7(b)^0-2=7(1)-2=7-2→f(0)=5→(x,f(x))=(0,5) Ok
2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No
3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No
4.) f(x)=-5(b)^x+10
x=0→f(0)=-5(b)^0+10=-5(1)+10=-5+10→f(0)=5→(x,f(x))=(0,5) Ok
5.) f(x)=2(b)^x+5
x=0→f(0)=2(b)^0+5=2(1)+5=2+5→f(0)=7→(x,f(x))=(0,7) No
Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10
line given slope = x coefficient = 1/3
Perpendicular slopes must be opposite reciprocals of each other: m1 * m2 = –1
line slope (m) = -3
line equation formula = y = mx + b
y = -3x + b
from the point given
x = 3
y= 3
3 = -9 + b
b = 12
y = -3x + 12
