Step-by-step explanation:
if that is truly the full problem description, then we have
10x - x + 5 = 41
=>
9x = 36
our simply
x = 4
so, I am not sure, what your teacher wants to see as result.
there is an infinite number of equations I could find, all with the solution x = 4.
Answer:
Look at the proof down
Step-by-step explanation:
The given is;
→ ∠1 and ∠2 form a linear pair
→ ∠1 ≅ ∠3
We want to prove;
→ ∠2 and ∠3 are supplementary
<em>We will write the proof in like a table</em>
1. ∠1 and ∠2 formed a linear pair ⇒ 1. Given
2. m∠1 + m∠2 = 180° ⇒ 2. Sum of angles on a straight line
3. ∠1 and ∠2 are supplementary angles ⇒ 3. Supplementary angles add up to 180°
4. ∠1 ≅ ∠3 ⇒ 4. Given
5. m∠2 + m∠3 = 180° ⇒ 5. Substitution method
6. ∠3 is a supplement of ∠2 ⇒ 6. Supplement of equal angles
7. ∠2 and ∠3 are supplementary ⇒ 7. Proved
100,000 (sorry if I'm wrong)
Answer:
x=4
Step-by-step explanation:
AB + BC = AC
AB= 6x, BC= x-5, AC= 23
Substituting what we know
6x + x-5 = 23
Combine like terms
7x -5 = 23
Add 5 to each side
7x-5+5 =23+5
7x = 28
Divide each side by 7
7x/7 = 28/7
x=4
Answer:
Step-by-step explanation:
Eliminate answer 4 immediately, because (4)(3) is not 7.
Look at answer 2: 7x + 3x = 10x, which does not match the middle term 12x in the original polynomial. Eliminate answer 2.
Look at answer 1: 1x + 21x = 22x, which does not match the middle term of the original polynomial. Eliminate answer 1.
All quadratics have solutions. Let's apply the quadratic formula to 3x^2 + 12x + 7: Here a = 3, b = 12 and c = 7, so that the discriminant b²-4ac is
12²-4(3)(7), or 144 - 84, or 60. Being positive, this tells us that the given poly has two real, unequal roots:
-12 ± √60 -12 + 2√15 -12 - 2√15
x = ----------------- = ------------------- and x = --------------------
3 3 3
Normally, if c is a root, then x - c is a factor.
If we try this here, however, the resulting factors do not at all match any of your answer choices.
Don't be offended...but please ensure you have copied this problem down correctly.
