Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
435 being the constant means that is what they started with
Hope this helps :)
Answer:
Option A. True
Step-by-step explanation:
we know that
<u>The Triangle Inequality Theorem</u>, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side
we have
4,3 and 6
Applying the triangle inequality theorem
case 1) 4+3 > 6 -----> is true
case 2) 3+6 > 4 ----> is true
therefore
The given segments could form a triangle
Is true
<span>1. </span>The probability that one of the diners orders fish = number of diners who ordered fish / total number of diners
p1=45/100=0.45
<span>2. </span>The probability that one of the diners is wearing dress= number of diners wearing dress/ total number of diners
<span>3. </span>p2=14/100=0.14
<span>The probability that one of the diners ordered the fish or is wearing a dress is: p=0.45+0.14=0.59</span>
Answer:
2d, 3b
Step-by-step explanation:
pay attention in class
these are simple theorems
i wish you all the best
if you want, i can explain them to you
