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vampirchik [111]

4 years ago

11

In a group of 50 students, 12 study geography, 9 study history and 6 of these students both geography and history. What is the p

robability that a student at random from the group, studies neither history nor geography?

1 answer:

xz_007 [3.2K]4 years ago

8 0

Answer:

The probability is 44/50 or 88%

Step-by-step explanation:

So from 50 you subtract 6 which equals 44.

So it is 44/50 = 88%

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At a school, 40% of the sixth grade students said that hip hop is their favorite kind of music. if 100 sixth grade students perf

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Answer:

Step-by-step explanation:

250 students are in the 6th grade have a good night it is night hear if you live in America east side 10:34 PM

6 0

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Express the polynomial below in the form P(x) = (x - k) times the quotient plus the remainder for the given value of k. P(x) = 3

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Step-by-step explanation: Please find the attached files for the solution

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An empty box has a mass of 2.75 kilograms. An electronics store is packing 5 identical laptops in the shipping box. Each laptop

Afina-wow [57]

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6 0

4 years ago

Jack’s bill at a restaurant came to $52.31. He wants to leave a 15% tip. How much will the new total be, including tip?

blondinia [14]

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4 0

4 years ago

If 10000 is invested at an interest rate of 10 per year ,compound semiannually,find the value of the investment after the given

slega [8]

Answer:

Part a) $\$17,958.56$

Part b) $\$32,251.00$

Part c) $\$57,918.16$

Step-by-step explanation:

<u><em>The complete question is</em></u>

If $10,000 is invested at an interest rate of 10% per year, compounded semiannually, find the value of the investment after the given number of years. (Round your answers to the nearest cent.)

a)6 years

b)12 years

c)18 years

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) 6 years

we have

$t=6\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2$

substitute in the formula above

$A=10,000(1+\frac{0.10}{2})^{2*6}$

$A=10,000(1.05)^{12}$

$A=\$17,958.56$

Part b) 12 years

we have

$t=12\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2$

substitute in the formula above

$A=10,000(1+\frac{0.10}{2})^{2*12}$

$A=10,000(1.05)^{24}$

$A=\$32,251.00$

Part c) 18 years

we have

$t=18\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2$

substitute in the formula above

$A=10,000(1+\frac{0.10}{2})^{2*18}$

$A=10,000(1.05)^{36}$

$A=\$57,918.16$

7 0

4 years ago