Answer:
1) 65 m
2) 40 m/s downward
Explanation:
Using for both questions the kinematic equation
v² = u² + 2as
and ignoring air resistance.
1) h = 60 + √(20²/(2(9.8))) = 64.51753...
2) v = √(20² + 2(9.8)(60)) = 39.69886...
<span>The wavelength of a wave is
A) how strong the wave is.
B) the distance between a peak of the wave and the next trough.
C) the distance between two adjacent peaks of the wave.
D) the distance between where the wave is emitted and where it is absorbed.
E) equal to the speed of the wave times the wave's frequency.</span><span>
the right answer is C
C) the distance between two adjacent peaks of the wave.</span>
The complete question in the attached figure
Let
c ------------------- > is the speed of light
v ------------------- > is the speed in medium
n ------------------- > is the refractive index of medium
we know that
c/v = n
n = (3 x 10^8)/(2.04 x 10^8) = 1.47
1.47 is the refractive index of glycerol.
therefore
the answer is (4) glycerol
Answer:
<h2>2 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>2 m/s²</h3>
Hope this helps you
Answer:
Their common velocity after collision is 3.6 m/s
Explanation:
Given;
mass of the first meatball, m₁ = 3.0 kg
initial velocity of the first meatball, u₁ = 6.0 m/s
mass of the second meatball, m₂ = 2.0 kg
initial velocity of the first meatball, u₂ = 0 m/s
let their common velocity after collision = v
Apply the principle of conservation of linear momentum for inelastic collision ;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(3 x 6) + (2 x 0) = v( 3 + 2)
18 = 5v
v = 18 / 5
v = 3.6 m/s
Therefore, their common velocity after collision is 3.6 m/s